2017-08-16 116 views
0

我正在尝试构建Restful Web服务。我的Maven项目名称是其他我正在关注Spring's Building a RESTful Web Service这样做,但我不想使用Spring Boot,只是创建一个war并将其托管在我的eclise/STS的Tomcat中。这里是我的web.xml和XX-servlet.xml的文件:在运行Spring Restful web服务时没有Spring Boot的问题

的web.xml

<web-app> 
    <display-name>Archetype Created Web Application</display-name> 

    <!-- The front controller of this Spring Web application, responsible for handling all application requests --> 
    <servlet> 
     <servlet-name>rest</servlet-name> 
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 
    <!-- Map all requests to the DispatcherServlet for handling --> 
    <servlet-mapping> 
     <servlet-name>rest</servlet-name> 
     <url-pattern>/*</url-pattern> 
    </servlet-mapping> 
</web-app> 

休息-servlet.xml中

<?xml version="1.0" encoding="UTF-8"?> 
<beans xmlns="http://www.springframework.org/schema/beans" 
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns:context="http://www.springframework.org/schema/context" 
     xmlns:mvc="http://www.springframework.org/schema/mvc" 
     xmlns:aop="http://www.springframework.org/schema/aop" 
     xmlns:p="http://www.springframework.org/schema/p" 
     xmlns:security="http://www.springframework.org/schema/security" 
     xsi:schemaLocation="http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-4.0.xsd 
     http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd 
     http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.2.xsd 
     http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd 

     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd"> 

     <context:annotation-config /> 
     <context:component-scan base-package="com.rest" /> 
     <mvc:annotation-driven/> 


</beans> 

GreetingController.java

@RestController 
public class GreetingController2 { 
    private final AtomicLong counter = new AtomicLong(); 

    @RequestMapping("/greeting") 
    public Greeting greeting(@RequestParam(value = "name", defaultValue = "World") String name) { 
     return new Greeting(counter.incrementAndGet(), String.format("Hello %s", name)); 
    } 
} 

当我在Tomcat上运行此URL时:http://localhost:8080/rest给出了404,我在tomcat控制台Aug 16, 2017 3:59:28 PM org.springframework.web.servlet.PageNotFound noHandlerFound WARNING: No mapping found for HTTP request with URI [/rest/] in DispatcherServlet with name 'rest' 中看到此消息,而我确实有映射。

而当我点击http://localhost:8080/rest/greeting时,我得到http 406,消息The resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers.,而根据教程,它应该转换为JSON,它可以在浏览器中呈现。

我花了很多时间试图弄清楚,看着SO上的各种帖子,以找出什么是错的,但不能。

+0

阿克沙伊塔瓦的回答帮我找到这个问题。除了他提到的之外,我没有Jackson JSON依赖性,这就是为什么它无法将我的对象转换为JSON。当我将它们添加到我的pom.xml中时,我可以看到http:// localhost:8080/rest/greeting正在工作。 – Learner

回答

3

你不必像
@RequestMapping(“/”)
根据您的代码默认映射你上面应该有以下网址做工精细
http://localhost:8080/rest/greeting

+0

我得到了http406消息'由这个请求标识的资源只能根据请求“接受”标题生成不可接受的特征响应.'对于http:// localhost:8080/rest/greeting – Learner

+0

添加所有的杰克逊JAR依赖关系,如果已经添加,然后添加接受头作为applciation/JSON。如果你使用chrome,那么更喜欢使用postman rest客户端,并将accept头改为application/json。杰克逊的依赖包括jackson-core,jackson-databing,jackson-annotations –

+0

我明白了,当我从我的方法返回一个String时,它会呈现它。所以是的,这是与将对象转换为JSON不起作用。我会尝试你的建议。谢谢Akshay +1 – Learner