我有一个表单,我可以编辑内容,此时我将复选框的值复制到输入字段中,但我宁愿保留原始复选框的并显示哪一个被检查。回复检查哪个复选框被选中
<div class="col-sm-9">
<label class="checkbox-inline">
<input type="radio" class="px" name="radiochoice" id="radio11" class="radio" value="No Charge" />
<span class="lbl">No Charge</span>
</label>
<br>
</div>
<div class="col-sm-9">
<label class="checkbox-inline">
<input type="radio" class="px" name="radiochoice" id="radio7" class="radio" value="185.00" />
<span class="lbl">Networking: $185.00</span>
</label>
<br>
</div>
<div class="col-sm-9">
<label class="checkbox-inline">
<input type="radio" class="px" name="radiochoice" id="radio8" class="radio" value="125.00"/>
<span class="lbl">Mechanical: $125.00</span>
</label>
<br>
</div>
如果我回显其刚刚显示的值,我该如何显示哪个复选框被选中?
value=<?php echo $radiochoice;?>>
目标:
if ($radiochoice == "No Charge") {
echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio11" class="radio" value="No Charge" checked/>';
echo '<span class="lbl">No Charge</span>';
echo '</label>';
echo '<br>';
echo '</div>';
echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio7" class="radio" value="185.00" />';
echo '<span class="lbl">Networking: $185.00</span>';
echo '</label>';
echo '<br>';
echo '</div>';
echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio8" class="radio" value="125.00" />';
echo '<span class="lbl">Mechanical: $125.00</span>';
echo '</label>';
echo '<br>';
echo '</div>';
echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio9" class="radio" value="59.00" />';
echo '<span class="lbl">Remote half: $59.00</span>';
echo '</label>';
echo '<br>';
echo '</div>';
echo '<div class="col-sm-9">';
echo '<label class="checkbox-inline">';
echo '<input type="radio" class="px" name="radiochoice" id="radio10" class="radio" value="89.00" />';
echo '<span class="lbl">Remote 1 HR: $89.00</span>';
echo '</label>';
echo '<br>';
echo '</div>';
} elseif ($answer == 185.00) {
等等等等
为什么mysql标记?没有支持它的代码。那是你的完整代码?你使用js/ajax还是直接'
要么等待一个神奇的答案,要么已经离开或者忽略了我的上述评论。请展示一些努力。 –
@ Fred-ii-魔术已经提供:-) – 2016-11-15 23:30:52