我正在尝试使用下面的php准备语句在mysql表中插入一行,但代码始终通过语句并移至echo“failed”。下面的代码中缺少什么?使用PHP准备的MYSQL插入语句
(我的数据库中有额外的列,但我没加它,因为我不想里面插入值(这些列中的一个自动递增))
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC) Where (ActivityDate=? AND CoreSite=? AND ActionAuditor=? AND DCOSPOC=?)"))
{
$stmt->bind_param("ssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
?>
我已经editied代码使用价值,而不是,它不回送失败,但成功的呼应..但仍然没有增加值数据库
<?php
$ActivityDate = $_POST["ActivitytDate"];
$CoreSite = $_POST["CoreSite"];
$ActionAuditor = $_POST["ActionAuditor"];
$DCOSPOC = $_POST["DCOSPOC"];
$AreaOwner = $_POST["AreaOwner"];
$ActionImplementer = $_POST["ActionImplementer"];
$ActionOwner = $_POST["ActionOwner"];
$MailSubject = $_POST["MailSubject"];
$ActionType = $_POST["ActionType"];
$RequestType = $_POST["RequestType"];
$RequestNumber = $_POST["RequestNumber"];
$OpenTime = $_POST["OpenTime"];
$CloseTime = $_POST["CloseTime"];
$ActionResult = $_POST["ActionResult"];
$Violation = $_POST["Violation"];
$ActionDetails = $_POST["ActionDetails"];
$Snags = $_POST["Snags"];
$SnagDesc = $_POST["SnagDesc"];
$Layout = $_POST["Layout"];
$LayoutDesc = $_POST["LayoutDesc"];
$CabinetLocation = $_POST["CabinetLocation"];
$Mapping = $_POST["Mapping"];
$MappingDesc = $_POST["MappingDesc"];
$Notes = $_POST["Notes"];
if($stmt = $mysqli->prepare("Insert INTO DCO_Database (ActivityDate, CoreSite, ActionAuditor, DCOSPOC, AreaOwner, ActionImplementer, ActionOwner, MailSubject, ActionType, RequestType, RequestNumber, OpenTime, CloseTime, ActionResult, Violation, ActionDetails, Snags, SnagDesc, Layout, LayoutDesc, CabinetLocation, Mapping, MappingDesc, Notes) values (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)"))
{
$stmt->bind_param("ssssssssssssssssssssssss", $ActivityDate, $CoreSite, $ActionAuditor, $DCOSPOC, $AreaOwner, $ActionImplementer, $ActionOwner, $MailSubject, $ActionType, $RequestType, $RequestNumber, $OpenTime, $CloseTime, $ActionResult, $Violation, $ActionDetails, $Snags, $SnagDesc, $Layout, $LayoutDesc, $CabinetLocation, $Mapping, $MappingDesc, $Notes);
$stmt->execute();
$stmt->close();
}
else{
echo ("Failed");
$mysqli->close();
}
echo ("Successful");
?>
您不能在INSERT查询中使用where子句。我认为你正在寻找更新! – Saty
它看起来像类对象''mysqli''的“准备”方法(顺便说就是在你的代码中没有定义)正在返回一个falsy值。您可能需要重新访问该部分,或者粘贴处理数据库内容的类中的代码。 – designcise
插入查询应该看起来像这样:INSERT INTO table_name(column1,column2,column3,...) VALUES(value1,value2,value3,...);' – Matheno