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我学会知道从URL中实际链接重定向的位置。 经过testinf重定向URL网站,它给了url重定向类型301. 所以,我测试基于下面的链接来获得真正的链接。 Get hold of redirect url with Java org.apache.http.client用Java重定向URL类型301
代码看起来象下面这样:
HttpGet httpget = new HttpGet(filename);
HttpContext context = new BasicHttpContext();
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse response = httpClient.execute((HttpUriRequest) httpget, context);
if (response.getStatusLine().getStatusCode() != HttpStatus.SC_OK)
throw new IOException(response.getStatusLine().toString());
HttpUriRequest currentReq = (HttpUriRequest) context.getAttribute(ExecutionContext.HTTP_REQUEST);
HttpHost currentHost = (HttpHost) context.getAttribute(ExecutionContext.HTTP_TARGET_HOST);
String currentUrl = currentHost.toURI() + currentReq.getURI();
System.out.println(currentUrl);
但我得到这样的信息:
的方法执行(HttpUriRequest,HttpContext的)在类型AbstractHttpClient不>适用于参数( HttpGet,HttpContext)
会有人帮我,这个代码有什么错?