2015-10-15 200 views
0

在PayPal的API文档页面上有以下命令。Curl命令通过SSH工作,但不通过PHP

curl -s --insecure -H "X-PAYPAL-SECURITY-USERID: caller_1312486258_biz_api1.gmail.com" -H "X-PAYPAL-SECURITY-PASSWORD: 1312486294" -H "X-PAYPAL-SECURITY-SIGNATURE: AbtI7HV1xB428VygBUcIhARzxch4AL65.T18CTeylixNNxDZUu0iO87e" -H "X-PAYPAL-REQUEST-DATA-FORMAT: JSON" -H "X-PAYPAL-RESPONSE-DATA-FORMAT: JSON" -H "X-PAYPAL-APPLICATION-ID: APP-80W284485P519543T" https://svcs.sandbox.paypal.com/AdaptivePayments/Pay -d "{\"actionType\":\"PAY\", \"currencyCode\":\"USD\", \"receiverList\":{\"receiver\":[{\"amount\":\"1.00\",\"email\":\"[email protected]\"}]}, \"returnUrl\":\"http://www.example.com/success.html\", \"cancelUrl\":\"http://www.example.com/failure.html\", \"requestEnvelope\":{\"errorLanguage\":\"en_US\", \"detailLevel\":\"ReturnAll\"}}" 

通过SSH运行此命令会产生成功响应。

我试图让这个确切的命令通过PHP CURL运行,但不断收到错误消息,说明API凭据不正确。因为这显然不是这种情况(否则上述命令会产生类似的响应)除了我的代码有问题之外,我不能得出任何结论,但是现在几天来一直困扰着我的错误:

$baseurl = 'https://svcs.sandbox.paypal.com/AdaptivePayments/Pay'; 

define('PAYPAL_API_USER', 'caller_1312486258_biz_api1.gmail.com'); 
define('PAYPAL_API_PWD', '1312486294'); 
define('PAYPAL_API_SIGNATURE', 'AbtI7HV1xB428VygBUcIhARzxch4AL65.T18CTeylixNNxDZUu0iO87e'); 
define('PAYPAL_API_APPLICATION_ID', 'APP-80W284485P519543T'); 

$returnurl = "http://www.returnurl.net"; 
$cancelurl = "http://www.cancelnurl.net"; 

$data = array(
    "actionType" => "PAY", 
    "currencyCode" => "USD", 
    "receiverList" => array(
     "receiver" => array(
      array(
       "amount" => "1.00", 
       "email" => "[email protected]" 
      ), 
     ) 
    ), 
    "returnUrl" => $returnurl, 
    "cancelUrl" => $cancelurl, 
    "requestEnvelope" => array(
     "errorLangauge" => "en_US", 
     "detailLevel" => "ReturnAll", 
    ) 
); 

$headers = array(
    "X-PAYPAL-SECURITY-USERID: ".PAYPAL_API_USER, 
    "X-PAYPAL-SECURITY-PASSWORD: ".PAYPAL_API_PWD, 
    "X-PAYPAL-SECURITY-SIGNATURE: ".PAYPAL_API_SIGNATURE, 
    "X-PAYPAL-SECURITY-REQUEST-DATA-FORMAT: JSON", 
    "X-PAYPAL-SECURITY-RESPONSE-DATA-FORMAT: JSON", 
    "X-PAYPAL-SECURITY-APPLICATION-ID: ".PAYPAL_API_APPLICATION_ID, 
); 

$ch = curl_init(); 
curl_setopt ($ch, CURLOPT_URL, $baseurl); 
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, TRUE); 
curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); 
curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, FALSE); 
curl_setopt ($ch, CURLOPT_POSTFIELDS, json_encode($data)); 
curl_setopt ($ch, CURLOPT_HEADER, $headers); 
print_r(curl_exec($ch)); 

任何人都可以发现此代码有什么问题吗?

再一次,我必须强调,这完全是PHP CURL问题,而不是Paypal问题。

+1

你不应该包括您的安全密钥/密码....这是一个公开的论坛.. – Darren

+0

达伦 - 这些都是一个PayPal文档页面上公布公立:https://开头开发商.paypal.com /文档/经典/自适应支付/ gs_AdaptivePayments /。我当然绝不会发布我自己的 –

+0

只是看着我的朋友:-) – Darren

回答

4

嗯,尝试:

curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); 

使用CURLOPT_HTTPHEADER代替CURLOPT_HEADERCURLOPT_HEADER只是一个标志,如果你想在输出中看到响应的标题,你可以使用它。

来源:http://php.net/manual/ro/function.curl-setopt.php

+0

这就做到了! :) –

相关问题