通知系统获取所有新记录

因此，我构建了所有基本功能，但存在一个主要缺陷。我从最后插入的ID进行搜索，这是很好..但错误是当我到PHP。我搜索MAX id，它会明显地发回最后一条记录。但是，如果用户执行了三个向您发送通知的操作，则其他两个操作不会通过该调用显示，只有在页面刷新时才会显示。通知系统获取所有新记录

那么，如果每次调用都是从前端搜索的最后一个ID开始，那么我需要更改哪些数据库中的所有通知？我认为可能是PHP页面中的while循环而不是最大的id。但那么后端如何从前端选择所有新数据最后的最大ID？

所以这就是我所拥有的。

<? 

$user1_id=mysqli_real_escape_string($mysqli,$_SESSION['id']); 
$call="select MAX(notification_id) AS notification_id ,notification_status,notification_targetuser,notification_triggeredby,notification_throughurl from notifications WHERE notification_targetuser='$user1_id' AND notification_status=1 ORDER BY notification_id DESC LIMIT 1"; 
     $chant=mysqli_query($mysqli,$call) or die(mysqli_error($mysqli)); 


while($notification=mysqli_fetch_array($chant)){ 
?> 
<script type="text/javascript"> 

var notification_id="<?php echo $notification['notification_id']?>"; 
var notification_targetuser="<?php echo $notification['notification_targetuser']?>"; 
var notification_triggeredby="<?php echo $notification['notification_triggeredby']?>"; 
function loadIt() { 

$.ajax({ 
type: "GET", 
url: "viewajax.php?notification_id="+notification_id+"&notification_targetuser="+notification_targetuser+"&notification_triggeredby="+notification_triggeredby, 
dataType:"json", 
success: function(data){ 
if(data.notification_id>notification_id){ 
$("#notif_ui"+notification_id).prepend('<div class="notif_text"><div id="notif_actual_text-" class="notif_actual_text"><img border="1" src="userimages/cropped'+data['notification_triggeredby']+'.jpg" onerror=this.src="userimages/no_profile_img.jpeg" width="40" height="40" ><br /><a href="'+data['notification_throughurl']+'">'+data['notification_content']+' </a><br />'+data['notification_time']+'<br/></div></div></div><hr/>'); 
i = parseInt($("#mes").text()); $("#mes").text((i+data.num)); 

    if(!data.notification_id.length) { 
    //no results... 
    return; 
} 
notification_id = data.notification_id; 
} 
} 
}); 
} 
setInterval(loadIt, 10000); 
</script>

PHP

$json = array(); 
    $com=mysqli_query($mysqli,"select MAX(notification_id) AS notification_id,notification_content,notification_time,notification_triggeredby,notification_throughurl from notifications where notification_id > '$id' AND notification_targetuser=".$_GET['notification_targetuser']." AND notification_triggeredby=".$_GET['notification_triggeredby']." AND notification_status=1"); 

    $num = mysqli_num_rows($com); 
    if($num>0){ 

     $json['num'] = $num; 
    }else{ 
     $json['num'] = 0; 
    } 
    $resultArr = mysqli_fetch_array($com); 
    $json['notification_id'] = $resultArr['notification_id']; 
    $json['notification_content'] = $resultArr['notification_content']; 
    $json['notification_throughurl'] = $resultArr['notification_throughurl']; 
    $json['notification_triggeredby'] = $resultArr['notification_triggeredby']; 
    $json['notification_time'] = $resultArr['notification_time']; 
    mysqli_free_result($com); 

    echo json_encode($json); 
    }

来源

2015-11-05 The River Scene Music

好吧我已经做了更多的研究，因为这似乎没有太多。显然在客户端搜索最大记录，然后将其与id>超过服务器端select中的记录进行比较。解决方案：[link]（http://stackoverflow.com/questions/3665227/whats-the-fastest-way-to-poll-a-mysql-table-for-new-rows） –

我实际上while循环防止多于一组的结果返回的内使用mysqli_free_result($com);，因此从查询中删除此。

来源

2015-11-05 16:04:44

通知系统获取所有新记录

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