jqgrid列中的图像链接

Question

我想在图像名称为查询字符串的jqgrid的列中显示图像链接。链接应包含以下路径“Home \ ShowImage？imageName = vlaue”。

Answer 1

function jqGridFormatter(cell, options, row) { 
    return "<a href='Home\ShowImage?imageName=" + cell + ">Image</a>"; 
} 

然后你需要指定该格式在jqGrid的colModel选项，请参见http://www.trirand.com/jqgridwiki/doku.php?id=wiki:custom_formatter。

Answer 2

您可以在URL参数通过XML或JSON移动图像是这样的：

$image = "<a href='#'><img src='folders/images/arrow.jpg' border='0' valign='middle' title='Edit something'><a>"; 



    echo "<?xml version='1.0' encoding='iso-8859-1'?$et\n"; 
    echo "<rows>"; echo "<page>".$page."</page>"; 
    echo "<total>".$total_pages."</total>"; 
    echo "<records>".$count."</records>"; // be sure to put text data in CDATA 

     echo "<row id='". $id."'>"; 
     echo "<cell>". $image."</cell>"; 
     echo "</row>"; 
     } 
    echo "</rows>"; 

请注意，应写为<一>