Angular 2 rxjs超时回调

Question

我想在HTTP调用发生超时事件时向用户提供反馈。

我尝试这样做：

return this._http 
       .post(apiUrl + 'Search/Everything', params, {withCredentials: true, headers: this.headers}) 
       .timeout(5000, this._feedbackService.error("Custom error message")) 
       .map((response: Response) => response.json().data); 

但是，只要HTTP调用时将触发反馈服务。

超时启动时如何启动服务？

Answer 1

假设_feedbackService.error返回Error，你应该能够做你需要与timeoutWith和​​运营商什么：

import "rxjs/add/observable‌​/defer"; 
import "rxjs/add/observable‌​/throw"; 
import "rxjs/add/operator/timeoutWith"; 
import { Observable } from "rxjs/Observable‌​"; 

return this._http 
    .post(apiUrl + 'Search/Everything', params, {withCredentials: true, headers: this.headers}) 
    .timeoutWith(5000, Observable.defer(() => Observable.throw(this._feedbackService.error("Custom error message")))) 
    .map((response: Response) => response.json().data);