1
我有多个xml/xhtml文件，我需要将列表中的列表进行转换。列表可以有两种不同的格式。我已经展示了每个清单的例子，并且它是理想的结果。示例1中的XSLT正常工作，但示例2中都使用了apply-templates employeesList和employeesList2模式。任何帮助获得理想的结果将不胜感激。使用XSLT更改XML/XHTML中的列表
实施例1：
<div class="company1">
<div class="employees-companyLabel">Employees:</div>
<ol class="company-employees">
<li class="company-employee">Joe Smith</li>
<li class="company-employee">Dave Jones</li>
<li class="company-employee">Bill Williams</li>
<li class="company-employee">Steve Hobbs</li>
<li class="company-employee">Jim Brown</li>
</ol>
</div>
期望的结果：
<div class="company2">
<div class="header">Employees:</div>
<ul class="employees">
<li class="employee">Joe Smith</li>
<li class="employee">Dave Jones</li>
<li class="employee">Bill Williams</li>
<li class="employee">Steve Hobbs</li>
<li class="employee">Jim Brown</li>
</ul>
</div>
实施例2：
<div class="company1">
<div class="employees-companyLabel">Employees:</div>
<div class="subhead-employees">Foreman:</div>
<ol class="company-employees">
<li class="company-employee">Joe Smith</li>
<li class="company-employee">Dave Jones</li>
</ol>
<div class="subhead-employees">Laborers:</div>
<ol class="company-employees">
<li class="company-employee">Bill Williams</li>
<li class="company-employee">Steve Hobbs</li>
<li class="company-employee">Jim Brown</li>
</ol>
</div>
期望的结果：
<div class="company2">
<div class="header">Employees:</div>
<ul class="employees">
<li class="positionTitle">Foreman</li>
<li class="employee">Joe Smith</li>
<li class="employee">Dave Jones</li>
<li class="positionTitle">Laborers</li>
<li class="employee">Bill Williams</li>
<li class="employee">Steve Hobbs</li>
<li class="employee">Jim Brown</li>
</ol>
</div>
XSLT：
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xhtml="http://www.w3.org/1999/xhtml" exclude-result-prefixes="xhtml">
<xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xhtml:div[@class='company1']">
<xsl:copy>
<xsl:attribute name="class">
<xsl:value-of select="'company2'"/>
</xsl:attribute>
<xsl:apply-templates select="@*[not(name()='class')]"/>
<xsl:apply-templates select="node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xhtml:div[@class='employees-companyLabel']">
<xsl:copy>
<xsl:attribute name="class">
<xsl:value-of select="'header'"/>
</xsl:attribute>
<xsl:apply-templates select="@*[not(name()='class')]"/>
<xsl:value-of select="translate(., ':', '')" />
</xsl:copy>
<xsl:element name="ul">
<xsl:attribute name="class">employees</xsl:attribute>
<xsl:apply-templates select="./following-sibling::xhtml:ol[@class='company-employees']" mode="employeesList" />
<xsl:apply-templates select="./following-sibling::xhtml:div[@class='subhead-employees']" mode="employeesList2" />
</xsl:element>
</xsl:template>
<xsl:template match="xhtml:ol[@class='company-employees']" mode="employeesList">
<xsl:for-each select="xhtml:li[@class='company-employee']">
<xsl:element name="li">
<xsl:attribute name="class">employee</xsl:attribute>
<xsl:apply-templates />
</xsl:element>
</xsl:for-each>
</xsl:template>
<xsl:template match="xhtml:div[@class='subhead-employees']" mode="employeesList2">
<xsl:element name="li">
<xsl:attribute name="class">
<xsl:value-of select="'positionTitle'"/>
</xsl:attribute>
<xsl:apply-templates />
</xsl:element>
<xsl:for-each select="./following-sibling::xhtml:ol[@class='company-employees'][1]/xhtml:li[@class='company-employee']">
<xsl:element name="li">
<xsl:attribute name="class">employee</xsl:attribute>
<xsl:apply-templates />
</xsl:element>
</xsl:for-each>
</xsl:template>
<xsl:template match="xhtml:div[@class='subhead-employees']" />
<xsl:template match="xhtml:ol[@class='company-employees']" />
<xsl:template match="xhtml:li[@class='company-employee']" />
</xsl:stylesheet>