我有领域数据库,其中包含数据和添加此数据的日期。我想解释这一点,并设置日期作为表视图节标题和数据作为每个部分的行数据取决于日期。我知道如何提取,但不知道如何按日期进行分组,并根据日期设置每个部分的数据。谢谢!iOS按领域按日期分组查看部分
4
A
回答
-8
您可以使用CoreData作为替代领域,并使用读取的结果控制,使您可以通过一些变种的数据和组排序。
3
您可以按日期对检索到的Results
进行排序,然后在迭代时对它们进行拆分,以便按照分组/层次的方式对其进行访问。
class Person {
dynamic var name = ""
dynamic var date = NSDate()
}
let sortedObjects = realm.objects(Person).sorted("date")
var lastDate = objects.first?.date
let calendar = NSCalendar.currentCalendar()
var lastGroup = [Person]()
var groups = [[Person]]()
for element in sortedObjects {
let currentDate = element.date
let difference = calendar.components([.Year, .Month, .Day], fromDate: lastDate!, toDate: currentDate, options: [])
if difference.year > 0 || difference.month > 0 || difference.day > 0 {
lastDate = currentDate
groups.append(lastGroup)
lastGroup = [element]
} else {
lastGroup.append(element)
}
}
groups.append(lastGroup)
注:这样一来,你就需要保持在内存中所有的元素。如果不适合你,根据你的使用情况,你可以只记住索引,而你可以使用它来访问检索到的Results
中的元素。
0
如果有人与雨燕3.0语法战斗:
var lastDate = dateObjects.first?.start
let calendar = Calendar.current
var lastGroup = [DateObject]()
var days = [[DateObject]]()
for dateObject in dateObjects {
let currentDate = dateObject.start
let unitFlags : Set<Calendar.Component> = [.era, .day, .month, .year, .timeZone]
let difference = calendar.dateComponents(unitFlags, from: lastDate!, to: currentDate)
if difference.year! > 0 || difference.month! > 0 || difference.day! > 0 {
lastDate = currentDate
days.append(lastGroup)
lastGroup = [travelTime]
} else {
lastGroup.append(dateObject)
}
}
days.append(lastGroup)
1
我有完全相同的问题,我需要在一个分区表中显示一种Realm实体,按日期分组,这就是我如何做到的。
包含日期字段Example类:
final class Appointment: Object {
@objc dynamic var id: Int = 0
@objc dynamic var date: Date?
}
示例代码,将得到所有的对象和他们的部分/结果拆分,通过独特的日期分组:
// (un)safely get an instance of Realm
let realm = try! Realm()
// get all the dates
// note that begginingOfDay is a extension on Date
// which gives back the beggining of the day of the given Date as a Date
// we are doing this in order to filter out non-unique dates later
let dates = self.realm.objects(Appointment.self).toArray().flatMap({ $0.date ?? nil }).map({ $0.beginningOfDay() })
// cast it to a Set to make values unique, and back to an Array for further use
let uniqueDates = Array(Set(dates))
let predicates = uniqueDates.map({ date -> NSPredicate in
// in order to use Swift's Date with NSPredicate
// it must be casted to NSDate
let begginingOfDay = date.beginningOfDay() as NSDate
let endOfDay = date.endOfDay() as NSDate
// create a predicate that checks if the given Date is in between
// the beggining of a given Date and the end of the given Date
let predicate = NSPredicate(format: "(date >= %@) AND (date <= %@)", begginingOfDay, endOfDay)
return predicate
})
// create an array of Results<Appointment>, and then use it to drive your table/collection view
// I will leave this part to you, depends on your UI implementation
// personally, I wrap this into another object that contains results, section index, section title, etc.
// and then I use all of that in my table view's data source methods
let sectionedResults: [Results<Appointment>] = predicates.map({ predicate -> Results<Appointment> in
let results = realm.objects(Appointment.self).filter(predicate)
return results
})
您现在应该有一个粗略的想法如何做到这一点,我将把UI实现的细节留给你。
相关问题
- 1. 按日期分组,看看日期是否为今天?
- 2. 按空组分组日期
- 3. 分组跨领域日期在SQL
- 4. Tableview部分按日期
- 5. SQL查询按日期分组时间
- 6. MySql查询 - 按日期范围分组?
- 7. NHibernate投影查询按日期分组
- 8. 按日期分组排序
- 9. 按日期分组ID
- 10. 不按日期分组?
- 11. MySQL:按日期分组RANGE?
- 12. 按月分组SAS日期
- 13. SQL按周分组日期
- 14. mySQL DateDiff按日期分组
- 15. 如何按日期按季度分组
- 16. MongoDB:按日期时间查询部分日期时间
- 17. 如何按星期分组日期?
- 18. 按星期,月份,日期分组
- 19. iOS分组按钮
- 20. MDX查询按日期按参数分组,具有天数
- 21. 按月份和星期分组,按日期时间列分组,按每月或每周的第一个分组
- 22. Mysql查询 - 在5分钟内按日期时间段分组
- 23. 按日期/时间的一部分#2
- 24. 如何按日期范围分组
- 25. 在linq中按日期分组
- 26. Telerik MVC Grid - 按日期分组
- 27. solrj中按日期字段分组
- 28. 分组结果按日期在MySQL
- 29. 分组按日期存储为VARCHAR2
- 30. SQL如何按日期范围分组
这是如何被接受的答案?问题是如何在Realm中实现这一点... – SiPe