对第二个标准之后的排序列表进行排序

Question

我有一个列表结果列表，并且我想在对象[]的内容之后对列表进行排序。所以我想在帐户'row [11]'后面排序，然后是'row'[1]'。我如何使用Groovy进行第二类？

 Object[] row = (Object[]) resultList.get(i); 
     String account = row[11]; 
     String vehicle = row[1]; 

例

Account  Vehicle 

    HKB   300 - PB 
    HKV   400 - PDAAA 
    HMN   200 - PBC200 
    HZA   155 - PCL 
    HZA   160 - PGA100 
    HZAB  165 - PGA100 
    HZAC  170 - PGA100 

代码

int execute(List <Object[]> resultList) { 

    Object[] row = null; 
    resultList = resultList.sort{ a,b -> a[11] <=> b[11]}; 
    //Then here I want to sort the sorted resultList after the vehicle also second group.  
    for (int i=resultList.size()-1; i >= 0; i--) { 
     row = (Object[]) resultList.get(i); 
     String account = row[11]; 
     String vehicle = row[1]; 

    } 

    return 1; 
} 

Answer 1

认为你只需要更换：

resultList = resultList.sort{ a,b -> a[11] <=> b[11]}; 

与

resultList = resultList.sort { a, b -> 
    a[11] <=> b[11] ?: a[1] <=> b[1] 
}