解析阵列串

Question

我有具有键值

Array ([0] =>stdClass Object ([privacy] => {"name": "on", "email": null, "mobile": null, "address": "on", "alt_contact": "on"})) 

我需要打印其中将包含逗号分隔键具有值“上”的字符串的对象阵列。结果字符串应该是

$result = "name,address,alt_contact"; 

请帮

Answer 1

这会做的伎俩你..

$json = '{"name": "on", "email": null, "mobile": null, "address": "on", "alt_contact": "on"}'; 
$array = json_decode($json,true); 

$str = ""; 
foreach($array as $key=>$value) 
{ 
    if($value == "on") 
     $str .= $key.","; 
} 
return rtrim($str,","); 

结果： - 姓名，地址，alt_contact

Answer 2

这就是您的请求转换为PHP的方式：

我需要

• 打印 - echo()
• 将包含分离逗号的字符串 - 它有值 '上' implode()
• 键 - array_keys()

这是直接从上面的列表中的代码：

$json = '{"name": "on", "email": null, "mobile": null, "address": "on", "alt_contact": "on"}'; 
// Pass TRUE as second argument to get arrays back; stdObject is useless 
$data = json_decode($json, TRUE); 

// print comma separated keys of 'on' 
echo(implode(',', array_keys($data, 'on'))); 

Answer 3

感谢Jaimin，它帮助

必须得到一个数组解析的$隐私对象

$userPrivacies = $userPrivacies[0]->privacy; 

后来使用你的代码。

使溶液变成

$userPrivacies = $userPrivacies[0]->privacy; 

$array = json_decode($userPrivacies,true); 

$str = ""; 
foreach($array as $key=>$value) 
{ 
    if($value == "on") 
     $str .= $key.","; 
} 
echo rtrim($str,",");