PHP DOM解析器：找到所有链接的文本并进行更改

Question

我是PHO DOM解析器的新成员。我有一个这样的字符串：

$coded_string = "Hello, my name is <a href="link1">Marco</a> and I'd like to <strong>change</strong> all <a href="link2">links</a> with a custom text"; 

，我想改变的链接的所有文本（在本例中，马尔科和链接）与自定义字符串，让说招呼。

如何在PHP上执行此操作？目前，我只initilized的XDOM/XPATH解析器：

$dom_document = new DOMDocument();  
$dom_document->loadHTML($coded_string); 
$dom_xpath = new DOMXpath($dom_document); 

Answer 1

你有一个良好的感觉对于此处的xpath，以下示例显示如何选择0123的所有文本节点子项（DOMText^Docs）种元素和改变自己的文字：

$dom_document = new DOMDocument();  
$dom_document->loadHTML($coded_string); 
$dom_xpath = new DOMXpath($dom_document); 

$texts = $dom_xpath->query('//a/child::text()'); 
foreach ($texts as $text) 
{ 
    $text->data = 'hello'; 
} 

让我知道这是有帮助的。

Answer 2

尝试phpQuery（http://code.google.com/p/phpquery/）：

<?php 

    $coded_string = 'Hello, my name is <a href="link1">Marco</a> and I\'d like to <strong>change</strong> all <a href="link2">links</a> with a custom text'; 

    require('phpQuery.php'); 

    $doc = phpQuery::newDocument($coded_string); 
    $doc['a']->html('hello'); 
    print $doc; 

?> 

打印：

Hello, my name is <a href="link1">hello</a> and I'd like to <strong>change</strong> all <a href="link2">hello</a> with a custom text 

Answer 3

<?php 

$coded_string = "Hello, my name is <a href='link1'>Marco</a> and I'd like to <strong>change</strong> all <a href='link2'>links</a> with a custom text"; 

$dom_document = new DOMDocument();  
$dom_document->loadHTML($coded_string); 
$dom_xpath = new DOMXpath($dom_document); 

$links = $dom_xpath->query('//a'); 
foreach ($links as $link) 
{ 
    $anchorText[] = $link->nodeValue; 
} 

$newCodedString = str_replace($anchorText, 'hello', $coded_string); 

echo $newCodedString;