我一直在尝试学习如何正确使用sys.argv,同时从命令行调用可执行文件。Python sys.argv打印函数结果的类型错误?
我想要在命令行传递文件名和参数时将函数结果打印到命令行,但是我得到一个TypeError。
到目前为止,我有:
#! /usr/bin/env python
import mechanize
from BeautifulSoup import BeautifulSoup
import sys
def dictionary(word):
br = mechanize.Browser()
response = br.open('http://www.dictionary.reference.com')
br.select_form(nr=0)
br.form['q'] = sys.argv
br.submit()
definition = BeautifulSoup(br.response().read())
trans = definition.findAll('td',{'class':'td3n2'})
fin = [i.text for i in trans]
query = {}
for i in fin:
query[fin.index(i)] = i
return query
print dictionary(sys.argv)
当我把这叫做:
./this_file.py 'pass'
我离开我与此错误消息:
Traceback (most recent call last):
File "./hot.py", line 20, in <module>
print dictionary(sys.argv)
File "./hot.py", line 10, in dictionary
br.form['q'] = sys.argv
File "/usr/local/lib/python2.7/dist-packages/mechanize/_form.py", line 2782, in __setitem__
control.value = value
File "/usr/local/lib/python2.7/dist-packages/mechanize/_form.py", line 1217, in __setattr__
raise TypeError("must assign a string")
TypeError: must assign a string
捷尔感谢您耐心等待,并回答我的问题。我应该强调一点,我没有使用sys.argv。我以为kwargs使用的列表和元组不是argv。 – tijko 2012-08-12 21:51:48
@tijko没问题。 *没有人*出生在这里知道Python(或其他任何东西:)从你以前的问题和错误消息,我怀疑这条线是问题。我希望这能解决你的问题。 – Levon 2012-08-12 21:53:02
对,并非常感谢。它解决了这个问题,我明白为什么! :D – tijko 2012-08-12 21:54:00