2017-09-01 426 views
0

我发现solution通过Windows命令行直接从环境变量PATH中删除某个目录。但我想通过从cmd文件中发出命令来达到相同的结果。使用cmd文件从PATH中删除不需要的目录

什么我能做的就是呼应我想PATH设置为结果,如果我把

echo %PATH:D:\dir-path;=% 

到我的CMD文件。但如果我写

set PATH=%PATH:D:\dir-path;=% 

PATH只包含我想要删除的目录。

此外,我想为导演路径使用一个变量,但如果我尝试结果更糟。我把

set dirPath=D:\dir-path 
echo %PATH:%dirPath%;=% 

和我所得到的全部是dirPath;=

我不知道如何解决这个问题,所以如果有人能够协助我会很感激。

编辑1

正如@Anders建议我现在有:

@echo off 

set exampleRemoveDir=d:\bar 

REM If I use %exampleRemoveDir% it does not work at all. 
call :removeFromPath exampleRemoveDir & set result=%ERRORLEVEL% 

:removeFromPath 
set removeDir=%~1 

setlocal enableextensions enabledelayedexpansion 
set _=!PATH:%removeDir%;=! 
if "%_%" == "%PATH%" set _=!PATH:%removeDir%=! 
endlocal & set PATH=%_% 
echo %PATH% 
exit /b 0 

但是与解决途径仍保持不变。代码完美无缺地工作,如果我没有将删除步骤的范围缩小,因为我想为多个目录执行该操作,如果没有这样一个好帮手为我完成这项工作真的很痛苦。

EDIT 2

因为这似乎比我还以为这里是我的完整不变的脚本,使复杂得多。

@echo off 
:: Switching Perl version from ActivePerl to StrawberryPerl or the other way round depending on which paths are set in 
:: PATH. 

:: Directories for ActivePerl 
set activePerl_SiteBinPath=D:\ProgramFiles\ActivePerl\site\bin 
set activePerl_BinPath=D:\ProgramFiles\ActivePerl\bin 

:: Directories for StrawberryPerl 
set strawberryPerl_SiteBinPath=D:\ProgramFiles\StrawberryPerl\perl\site\bin 
set strawberryPerl_BinCPath=D:\ProgramFiles\StrawberryPerl\c\bin 
set strawberryPerl_BinPath=D:\ProgramFiles\StrawberryPerl\perl\bin 

:: Determine which of the directories are present in PATH and which are not. 
call :isInPath %activePerl_SiteBinPath% & set foundActivePerl_SiteBinPath=%ERRORLEVEL% 
call :isInPath %activePerl_BinPath% & set foundActivePerl_BinPath=%ERRORLEVEL% 
call :isInPath %strawberryPerl_SiteBinPath% & set foundStrawberryPerl_SiteBinPath=%ERRORLEVEL% 
call :isInPath %strawberryPerl_BinCPath% & set foundStrawberryPerl_BinCPath=%ERRORLEVEL% 
call :isInPath %strawberryPerl_BinPath% & set foundStrawberryPerl_BinPath=%ERRORLEVEL% 

:: Test 
call :removeFromPath %strawberryPerl_SiteBinPath% & set removedStrawberryPerl_SiteBinPath=%ERRORLEVEL% 

rem if /i %foundActivePerl_SiteBinPath% equ 0 if /i %foundActivePerl_BinPath% equ 0 (
rem  if /i %foundStrawberryPerl_SiteBinPath% neq 0 if /i %foundStrawberryPerl_BinPath% neq 0 if /i %foundStrawberryPerl_BinCPath% neq 0 (
rem   echo Switching from ActivePerl to StrawberryPerl. 
rem   TODO 
rem   exit /b 0 
rem ) 
rem) 
rem 
rem if /i %foundStrawberryPerl_SiteBinPath% equ 0 if /i %foundStrawberryPerl_BinPath% equ 0 if /i %foundStrawberryPerl_BinCPath% equ 0 (
rem  if /i %foundActivePerl_SiteBinPath% neq 0 if /i %foundActivePerl_BinPath% neq 0 (
rem   echo Switching from StrawberryPerl to ActivePerl. 
rem   TODO 
rem   exit /b 0 
rem ) 
rem) 

:: Error 
:: TODO 
exit /b 

:isInPath 
:: Tests if the path stored within variable pathVar exists within %PATH%. 
:: 
:: The result is returned as the ERRORLEVEL: 
::  0 if the pathVar path is found in %PATH%. 
::  1 if pathVar path is not found in %PATH%. 
::  2 if parhVar path is missing or undefined. 

:: Error checking 
if "%~1"=="" exit /b 2 

set pathVar=%~1 

for /f %%i in ('echo ";%%PATH%%;" ^| find /c /i ";%pathVar%;"') do set /a foundPathVar=%%i 

if /i %foundPathVar% equ 0 (
    exit /b 1 
) 
exit b/ 0 

:removeFromPath 
:: Removes a given directory from environment variable PATH if the directory exists within PATH. 
:: 
:: The result is returned as the ERRORLEVEL: 
::  0 if the given directory was removed from PATH or if it didn't exist in PATH. 
::  1 if no directory was given or the directory is undefined. 

:: Error checking 
if "%~1"=="" exit /b 2 

set removeDir=%~1 

setlocal enableextensions enabledelayedexpansion 
set _=!PATH:%removeDir%;=! 
if "%_%" == "%PATH%" set _=!PATH:;%removeDir%=! 
endlocal & set PATH=%_% 
echo %PATH% 

exit /b 0 

编辑3

由于@Anders从路径现在删除目录工作正常。我删除了上面未定义参数的错误检查,并在函数调用的参数周围添加了%。 但不知何故:isInPath现在总是返回零。就我而言,这已经奏效了......:/此外,使用当前代码(在所有函数参数中添加了%),在调用:removeFromPath后,cmd总是直接关闭,而不管pause。真是令人生气!

+0

为什么你想从'%PATH%'变量删除位置?您是否知道,您在批处理/ cmd.exe会话中使用'SET'PATH =%PATH:match = replace%“进行的任何更改都不是先决条件,它只会持续与cmd实例一样长。你能否提供更多的批处理文件,以便我们更好地处理你希望达到的目标。 – Compo

+0

@Lilo,脚本中是否有其他功能可能导致问题?我测试了安德斯的脚本,确实确实删除了路径中的目录。 –

+0

从长远来看,我想使用setx,但只要它不能与set一起工作,为什么我会使用setx? 我已经安装了ActivePerl以及es StrawberryPerl,我希望能够通过简单地双击批处理脚本来切换当前使用的Perl变体。为了实现这一点,我必须检查哪些目录当前在PATH中,因此必须删除或添加以从当前使用的变体切换到另一个。 – Lilo

回答

2

如果您想使用另一个变量作为变量替换的一部分,则需要使用延迟扩展。您还需要处理您要移除的路径在%path%末尾的可能性,因此不会由;终止。

@echo off 

set removedir=d:\bar 
set PATH=c:\foo;%removedir%;y:\baz&REM Set example %path% 

echo Starting with %%PATH%% set to %PATH% 

setlocal enableextensions enabledelayedexpansion 
set _=!PATH:%removedir%;=! 
if "%_%" == "%PATH%" set _=!PATH:;%removedir%=! 
endlocal & set PATH=%_% 

echo %%PATH%% is now %PATH% 

,并在这里作为一个辅助功能:

@echo off 
goto start 

:removeFromPath 
echo.Debug: Starting function with remove=%~1 and %%PATH%%=%PATH% 
setlocal enableextensions enabledelayedexpansion 
set removedir=%~1 
set _=!PATH:%removedir%;=! 
if "%_%" == "%PATH%" set _=!PATH:;%removedir%=! 
endlocal & set PATH=%_% 
echo.Debug: Ending function with %%PATH%%=%PATH% 
goto :EOF 


:start 
set exampleremovedir=d:\bar 
set PATH=c:\foo;%exampleremovedir%;y:\baz&REM Set example %path% 

echo Starting with %%PATH%% set to %PATH% 

call :removeFromPath %exampleremovedir% 

echo %%PATH%% is now %PATH% 
+0

只要我不把它放到一个函数中, ':removeFromPath'我在那里设置removedir =%〜1',然后使用你的代码,即使在那个函数里面的回显显示了一个不变的路径,我在这里丢失了什么? – Lilo

+0

对我来说它工作得很好。 – Anders

+0

@Lilo有你试图在函数内部设置'setlocal enabledelayedexpansion'? –

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