从MySQL选择时仅本

Question

一个单线我有这样的MySQL查询：

SELECT a.full_address 
FROM games_server AS a 
JOIN orders_order AS b 
ON b.server_id = a.id 
WHERE service_type = 'color' 
AND status = 'running' ORDER BY RAND()" 

它完美细，并选择仅当SERVICE_TYPE是“颜色”的值。 但我需要的是，只有当只有一行service_type = color且没有其他行具有不同的service_type值时，才会选择'full_address'。因为对于一个full_address = a，可能有多行。例如。 full_address = a，service_type = color，同一个full_address = a，service_type = top。在那个特殊情况下，当它们中有两个时 - 它不能被选中。只有当有一行service_type = color时才有。

我希望任何人都能理解我说的话。对不起，如果我不能更清楚。

Answer 1

试试这个（假设games_server有ID）：

SELECT a.full_address FROM games_server AS a 
JOIN orders_order AS b ON b.server_id = a.id 
WHERE status = 'running' 
GROUP BY a.id 
HAVING group_concat(distinct service_type) = 'color' 
ORDER BY RAND() 

Answer 2

如果我理解正确你的问题，子查询应该是有用的在这里。

SELECT a.full_address 
FROM games_server AS a 
JOIN orders_order AS b 
ON b.server_id = a.id 
WHERE service_type in 
     (select service_type 
     from orders_order 
     group by service_type 
     having COUNT(service_type)=1) 
AND status = 'running' ORDER BY RAND()