线程退出由于未捕获的异常

Question

Hy！

我的代码：

Thread thread = new Thread(){ 
      @Override 
      public void run() { 
       while (true) 
       { 
        Handler handler = new Handler(){ 
          @Override 
          public void handleMessage(Message msg) { 

          if (msg.obj.toString()!= null) 
          { 
          JSONParse json = null; 
          try { 
           Log.e("Channel_State",msg.obj.toString()); 
           json = new JSONParse(msg.obj.toString()); 
           String state = json.getChannelState(); 
           id = state; 
           TextView tv2 = (TextView)findViewById(R.id.mainscreen_state); 
           tv2.setText("Channel State: "+ state); 
           Log.e("State",state); 
          } catch (final Exception e) { 
           // TODO Auto-generated catch block 
           e.printStackTrace(); 
           runOnUiThread(new Runnable() { 
            public void run() { 
             Toast toast ; 
             toast =  Toast.makeText(getApplicationContext(), "Error" + e.getMessage(), 500); 
             Log.e("Error",e.getMessage()); 
             toast.show(); 
            } 
           }); 
          } 

          } 
          else 
          { 

           runOnUiThread(new Runnable() { 
           public void run() { 
            Toast toast ; 
            toast =  Toast.makeText(getApplicationContext(), "error", 500); 

            toast.show(); 
           } 
          }); 
          } 
          } 
          }; 

        List<NameValuePair> params = new ArrayList<NameValuePair>(); 
        params.add(new BasicNameValuePair("session_id", settings.getString("session_id","error"))); 
        params.add(new BasicNameValuePair("channel_id",String.valueOf(settings.getInt("channel_id", -1)))); 
        HttpConnection con = new HttpConnection(params, "http://surfkid.redio.de/getChannelImage", handler); 
        con.start(); 
        try { 
         Log.e("Sleep","Begin"); 
         this.sleep(5000); 
         Log.e("Sleep","End"); 

        } catch (InterruptedException e) { 
         // TODO Auto-generated catch block 
         Log.e("Sleep","Fail"); 
        } 

       } 
      } 
     }; 
     thread.start(); 

登录：

02-10 00:01:29.044: ERROR/AndroidRuntime(1248): Uncaught handler: thread Thread-13 exiting due to uncaught exception 
02-10 00:01:29.054: ERROR/AndroidRuntime(1248): java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare() 
02-10 00:01:29.054: ERROR/AndroidRuntime(1248):  at android.os.Handler.<init>(Handler.java:121) 
02-10 00:01:29.054: ERROR/AndroidRuntime(1248):  at android.skiptvad.MainScreen$6$1.<init>(MainScreen.java:258) 
02-10 00:01:29.054: ERROR/AndroidRuntime(1248):  at android.skiptvad.MainScreen$6.run(MainScreen.java:258) 

请帮帮忙！

Answer 1

好像你想要做的是创造一个HandlerThread

HandlerThread myThread = new HandlerThread(); 
myThread.start(); 
Handler myHandler = new Handler(myThread.getLooper()){ 
//your handler code. 
} 

这应该给你的处理程序在你正在寻找的方式处理一个线程什么。

Answer 2

您正在工作线程中创建一个Handler。你不能那样做。处理程序需要在UI线程中实例化。

Answer 3

在实例化处理程序之前，您需要在线程中启动消息泵。一旦创建了处理程序，它就绑定到它创建的线程，并且可以向其发布消息。线程的例子：

class MyThread extends Thread 
    { 
     private CountDownLatch mSync = new CountDownLatch(1); 
      private Handler mHandler; 
    public Handler getHandler() 
     { 
      try//Make sure the handler has been created. 
      { 
      mSync.await(); 
      } 
      catch (InterruptedException e) 
      { 
       //Do something 
      } 
      return mHandler; 
     } 

      public void run() 
     { 
          Looper.prepare(); 
          
          mHandler = new Handler() 
      { 
              public void handleMessage(Message msg) 
       { 
        if (msg.what == one of your message) 
        { 
        //.... 
        } 
              } 
          }; 
          
      mSync.countDown(); 
          Looper.loop(); 
      } 
  } 

使用getHandler（）来处理程序返回到你的线程，然后将消息发送给它。