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不知道如何解决这个错误,我评论了代码中的错误,对于Java来说很新颖。我正尝试将我的卡片发送到我的构造函数中,并创建一个卡组数组。不兼容型卡无法转换为字符串
public abstract class CardGame {
protected String[] deck = new String[52];
private String[] Suit = {"Spade","Dimond","Heart","Club"};
private String[] Card = {"2","3","4","5","6","7","8","9","10","jack","queen","king","ace"};
public CardGame(){
int c = 0;
for (int x=0; x < Suit.length; ++x){
for (int i = 0; i < Card.length; ++i){
deck[c] = new Card(Suit[x], Card[i]); // heres the error
c++;
}
}
}
}
public class Card {
String suit;
String name;
public Card(String s,String n){
suit = s;
name = n;
}
public String getsuit(){
return suit;
}
public String getname(){
return name;
}
}
TYVM奏效,所以即时通讯与保护卡[] =甲板新卡猜测[52];我创建了一个卡数据类型数组? oop很混乱。 – user3538292 2014-10-07 02:40:07
@ user3538292将您的数据结构(您的数组)看作只适合特定类型对象的容器,就像一个蛋盒只能包含鸡蛋一样,或者一个保龄球包只能包含保龄球。保龄球不属于蛋壳,也不属于蛋壳。当你声明一个数据结构时,你也告诉Java编译器它内部属于什么类型的东西(特定类的典型对象或从该类继承的对象)。你编写得越多,你越习惯这个想法。请记住:每件事都有特定的地方。 – MarsAtomic 2014-10-07 18:54:11