问题背景:运行时错误:无法获取财产“顶”
我有一个导航栏是“顺利滚动”根据所选项目的ID对应的股利。
的问题:
在Chrome和Firefox有没有问题,当我尝试并选择从IE导航栏的选项(11版),下面的JavaScript错误显示:
0x800a138f - JavaScript runtime error: Unable to get property 'top' of undefined or null reference
的代码:
这是叔他JS代码为平滑滚动:
<script>
$(document).ready(function() {
$('#nav .navbar-nav li>a').on('click', function (event) {
event.preventDefault();
var sectionID = $(this).attr("href");
scrollToID(sectionID, 750);
});
function scrollToID(id, speed) {
var offSet = 70;
**ERROR LINE - IN IE ONLY:**
var targetOffset = $(id).offset().top - offSet;
$('html,body').animate({ scrollTop: targetOffset }, speed);
}
});
</script>
编辑 - 添加HTML标记:
导航栏:
<div class="navbar navbar-fixed-top">
<nav class="navbar navbar-default" role="navigation" id="nav">
<div class="container">
<div class="navbar-header">
<button type="button" class="navbar-toggle collapsed" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand logo"><img src="~/images/mE.png" id="logo" alt="Logo"></a>
</div>
<div class="collapse navbar-collapse" id="bs-example-navbar-collapse-1">
<ul class="nav navbar-nav">
<li class="dropdown">
<a href="#" class="dropdown-toggle" data-toggle="dropdown">Menu<span class="caret"></span></a>
<ul class="dropdown-menu" role="menu">
<li><a href="#myCarousel">Projects</a></li>
<li><a href="#Welcome">Welcome</a></li>
<li><a href="#features">Workplace, Education, Development</a></li>
<li><a href="#About">About Me</a></li>
<li><a href="#Location">Location</a></li>
</ul>
</li>
</ul>
</div>
</div>
</nav>
</div>
股利ID:
<div class="row">
<div class="col-sm-12 mePadding">
<div class="carousel slide" id="myCarousel">
/*CODE*/
</div>
</div>
</div>
我不明白当这段代码在Chrome上正常工作时,'top'属性如何可以为null或为空?
**** EDIT 2 - 增加了新的JavaScript代码:****
更多的实物指标调查误差被causied,因为这行后:
var sectionID = $(this).attr("href");
这是返回一个'未定义''sectionID'的属性。
我已经修改我的代码来实现 '数据ID' 下拉列表上的属性:
<ul class="dropdown-menu" role="menu">
<li><a href="#" data-id="myCarousel">Projects</a></li>
<li><a href="#" data-id="Welcome">Welcome</a></li>
<li><a href="#" data-id="features">Workplace, Education, Development</a></li>
<li><a href="#" data-id="About">About Me</a></li>
<li><a href="#" data-id="Location">Location</a></li>
JavaScript的平滑滚动,现在看起来是这样的:
$(document).ready(function() {
$('#nav .navbar-nav li>a').on('click', function (event) {
event.preventDefault();
var sectionID = $(this).data('data-id');
console.log('ID:'+sectionID);
scrollToID('#' + sectionID, 750);
});
function scrollToID(id, speed)
{
//alert('SectionID is: ' + id);
var offSet = 70;
var obj = $(id).offset();
var targetOffset = $(id).offset().top - offSet;
$('html,body').animate({ scrollTop: targetOffset }, speed);
}
});
如果我硬编码div ID例如'#myCarosuel',那么这完美的作品,即:
scrollToID('#myCarosuel, 750);
您使用jQuery的哪个版本? – dejakob 2014-10-19 19:41:53
@dejakob – user1352057 2014-10-19 19:44:49
只是为了抛出一些东西在墙,你有没有尝试在顶部添加圆括号?像“$(id).offset()。top()”? – trnelson 2014-10-19 20:28:11