如果/ else语句在循环内部被忽略

-1

当我运行这个，并且我遇到了情况1中表示“输入飓风＃1的最大速度：”的行时，我将输入“34”并且它将返回“风速在结：25.6789”“输入飓风＃2的最大风速：”但我试图让它返回“无效Windspeed为Hurrican，再试一次。”如果/ else语句在循环内部被忽略

#include <stdio.h> 
#include <stdlib.h> 

int main(int argc, char *argv[]) 
{ 
int x; 
int year; 
int tropical_storms; 
int hurricanes; 
int a=1; 
int windspeed; 
float knots; 
float conversion=0.868976; 
    printf("     HEg v1.0 \n"); 
    printf("0. Exit\n"); 
    printf("1. Submit Hurricane Season Storm Information\n"); 
    printf("2. Submit Storm Data\n"); 
    printf("3. Print Hurricane Season Analysis\n"); 
    printf("4. Print Storm Analysis\n"); 
    printf("\n"); 
    printf("Please Enter Selection: "); 
    scanf("%d", &x); 
    switch(x) { 
    case 0: 
      printf("Thank you for using HEg v1.0"); 
      break; 
    case 1: 
      printf("Enter the year: "); 
      scanf("%d", &year); 
      printf("Enter the number of tropical storms in 2009: "); 
      scanf("%d", &tropical_storms); 
      printf("Enter the number of Hurricanes in 2009: "); 
      scanf("%d", &hurricanes); 
      while(a<=hurricanes){ 
       printf("Enter the max windspeed of hurricane #%d: ", a); 
       scanf("%d", &windspeed); 
       a++; 
       if(windspeed>74){ 
       knots=windspeed*conversion; 
       printf("Wind speed in knots: %.4f \n", knots); 
       } 
       else{ 
       printf("Invalid Windspeed for Hurricane. Try again"); 
       } 
      } 

      break; 
    case 2: 
      printf("Menu option not available in HEg v1.0"); 
      break; 
    case 3: 
      printf("Menu option not available in HEg v1.0"); 
      break; 
    case 4: 
      printf("Menu option not available in HEg v1.0"); 
      break; 
    default: 
      printf("no");  
      break; 
    } 
    system("PAUSE>nul"); 
    return 0; 
}

来源

2014-09-26 CCorey

你为什么认为'if' /'else'语句被忽略？ – 2014-09-26 01:54:12

作为一名经验丰富的程序员，我可以向您保证，if语句不会被忽略:)请更新您的文章，说出*您预期会发生什么*以及*实际发生了什么*。还要描述你给了哪些输入来引起这种行为。 – 2014-09-26 02:06:06

目前尚不清楚“声明中的内容”的含义。 – 2014-09-26 02:06:31