使用标记方法替换Fibonacci系列中的多个数字

Question

正如标题所示，我有一个斐波那契数列的代码，我的目标是用系列数字替换数字中的多个数字（3,5,7和它们的组合）字。我被建议在我的if循环中使用一个标志来检查打印的短语，如果打印了该短语，则跳过该数字。从本质上讲，我想要的输出样子是：

1 1 2 8跳过跳过13 34 55

（这是只更换三个多，现在）。

相反，我所得到的是：

1 1 2 3 skip5 8月13日21 skip34 55

这里是我的代码截至目前：

int febCount = 50; 
long[] feb = new long[febCount]; 
feb[0] = 1; 
feb[1] = 1; 
for (int i = 2; i < febCount; i++) { 
feb[i] = feb[i - 1] + feb[i - 2]; 
} 

for (int i = 0; i < febCount; i++) { 
System.out.print(feb[i] + ((i % 10 == 9) ? "\n" : " ")); 
if (feb[i] % 3 == 0) 
    System.out.print("skip"); 
} 

任何及所有帮助不胜感激！

Answer 1

让我们来看看您提供的代码，并试图理解它为什么不起作用。

//The first thing we do is setup the loop to iterate through the fib numbers. 
//This looks good. 
for (int i = 0; i < febCount; i++) { 
//Here we print out the fibonacci number we are on, unconditionally. 
//This means that every fibonacci number will be printed no matter what number it is 
//we don't want that. 
System.out.print(feb[i] + ((i % 10 == 9) ? "\n" : " ")); 
//After we print the number, we check to see if it is a multiple of three. 
//maybe we should be waiting to print until then? 
if (feb[i] % 3 == 0) 
    System.out.print("skip"); 
} 

既然我们已经走过了代码，我们可以提出一个新的解决方案。 让我们尝试更新循环，以便它等待打印斐波那契数字，直到我们检查完它后是否符合条件。

for (int i = 0; i < febCount; i++) { 
    if (feb[i] % 3 == 0 || feb[i] % 5 == 0 || feb[i] % 7 == 0) { //check if multiple of 3 5 or 7 
     System.out.println(" Skip "); 
    } else { //if it's not a multiple, then print the number 
     System.out.println(" " + feb[i]); 
    } 
}