2012-03-18 104 views
1

所以我有以下的代码来检查称为Doctors.txt为什么我不能在我的项目中访问这个.txt文件?

文本文件

它具有以下信息:

35000 2000 AV122258C Dr Alex James CARDIO 
30500 2005 AB347433C Miss Elizabeth Kooper MB 
32653 1995 JA103240B Dr Mohammed Khan ON 
64400 2001 JG371458A Dr Tom Jacob CARDIO 
91000 2002 IH102411Y Dr Rahana Mohammed ON 
55000 1987 JJ405626N Dr Mary Francis AN 
87000 1988 WQ333452N Mr Mark Cromwell NEURO 
60500 1998 HK413942S Mr Victor Jacob GASTRO 
40000 2003 AJ103006X Dr Mia Larson GS 
42000 2003 ER148468D Dr Rizwan Hussain GS 
38000 2004 RB193984P Dr Lam Yeng HAE 

的类文件时,它自...

import java.io.PrintWriter; 
import java.io.FileReader; 
import java.util.Scanner; 
import java.io.IOException; 

public class FileHandler 
{ 
/** 
* Save all doctor records to a file 
* @param doctors the DoctorList to save 
*/ 
public void saveRecords(DoctorList doctors) 
{ 
     PrintWriter writer = null; 
    try 
    { // NB: the file name is hard-coded 
     writer = new PrintWriter("Doctors.txt"); 
     writer.println(doctors.toString()); 
     writer.flush(); 
    } 
    catch(IOException e) 
    { 
     System.out.println("Error writing file"); 
    } 
    finally 
    { 
     writer.close(); 
    } 
} 

/** 
* Load doctor records from the file 
* @param doctors the DoctorList to add doctors to 
*/ 
public void readRecords(DoctorList doctors) 
{ 
    FileReader reader = null; 
    try 
    { 
     // NB: the file name is hard-coded 
     reader = new FileReader("Doctors.txt"); 
     Scanner sc = new Scanner(reader); 

     String record; 
     String[] data; 
      Doctor doctor; 
     while(sc.hasNextLine()) 
     { 
      record = sc.nextLine(); 
      if(record.length() != 0) 
      { 
       data = record.split("\t", 5); 
         doctor = DoctorFactory.newDoctor(data[3], data[0], data[2], data[1], data[4]); 
       doctors.add(doctor); 
      } 
     } 
    } 
    catch(IOException e) 
    { 
     System.out.println("Error reading file"); 
     e.printStackTrace(); 
    } 
} 
} 

我已经把它放在像这样的相同区域内: enter image description here

但是,似乎当我运行主类时,它无法读取内容...

回答

1

路径是你的问题。试试这个:

reader = new FileReader("src/Doctors.txt"); 

一个更好的解决方案是不依赖于文件路径,并使用getResourceAsStream()CLASSPATH返回InputStream

0

当时的应用程序。是建立,文本'文件'通常会在一个罐子里面。它可以通过URL读取,但不能写入。


这样的“持久”式的资源通常的策略是把他们的user.home一个子目录,然后通过File

访问它们
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