我有这样的表变量:MySQL查询dont't使用索引时,有在WHERE
CREATE TABLE `ClientesHora_copy` (
`dia` varchar(6) default NULL,
`hora` varchar(2) default NULL,
`sit` varchar(17) default NULL,
`nodo` varchar(6) default NULL,
`clientes` decimal(41,0) default NULL,
`segundos` double default NULL,
`llamadas` decimal(41,0) default NULL,
`fecha` datetime default NULL,
KEY `nodo_fecha` (`nodo`,`fecha`),
KEY `nodo` (`nodo`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1
与此查询:
SET @sitio= 'ABA000';
SET @horaini='2013-02-12 15:18:00';
SET @horafin='2013-02-12 20:36:00';
EXPLAIN SELECT nodo,sit,clientes,segundos,llamadas,fecha,hora,@horaini AS horaini,@horafin AS horafin
FROM `ClientesHora_copy`
WHERE
nodo [email protected]
AND
fecha BETWEEN DATE_SUB(DATE_FORMAT(@horaini, "%Y-%m-%d %H:00:00"), INTERVAL 7 DAY)
AND DATE_SUB(DATE_FORMAT(@horafin, "%Y-%m-%d %H:00:00"), INTERVAL 7 DAY)
我有这样的解释
id select_type table type possible_keys key key_len ref rows Extra
------ ----------- ----------------- ------ ------------- ------ ------- ------ ------- -------------
1 SIMPLE ClientesHora_copy ALL (NULL) (NULL) (NULL) (NULL) 2716460 Using where
但是,如果我不使用@sitio变量(但使用@horaini,@horafin变量):
EXPLAIN SELECT nodo,sit,clientes,segundos,llamadas,fecha,hora,@horaini AS horaini,@horafin AS horafin
FROM `ClientesHora_copy`
WHERE
nodo ='ABA000'
AND
fecha BETWEEN DATE_SUB(DATE_FORMAT(@horaini, "%Y-%m-%d %H:00:00"), INTERVAL 7 DAY)
AND DATE_SUB(DATE_FORMAT(@horafin, "%Y-%m-%d %H:00:00"), INTERVAL 7 DAY)
我得到这个:
id select_type table type possible_keys key key_len ref rows Extra
------ ----------- ----------------- ------ --------------- ---------- ------- ------ ------ -------------
1 SIMPLE ClientesHora_copy range nodo_fecha,nodo nodo_fecha 18 (NULL) 1 Using where
为什么mysql的犯规使用索引与@sitio变量的任何想法,但它与@fechaini和@fechafin呢?
谢谢!
问题不在于缺少“常量”值(因为所选答案指示。这很容易证明MySQL将使用带用户变量的索引“const”ref。问题是字符集;用户变量可能与列不同。我们可以使用'CONVERT()'函数可以用来在不同的字符集之间进行转换。 – spencer7593 2013-02-22 21:39:45