PHP类问题

Question

我正在使用下面的代码，当运行时，屏幕上什么也没有显示。

class ModelBase 
{ 
    public $db_server; 
    public $db_user; 
    public $db_password; 
    static $db_conn; 

    public static $DBSERVER="localhost"; 
    public static $DBUSER="user"; 
    public static $DBPASSWORD="password"; 
    public static $DBNAME="test"; 

    function ModelBase() 
    { 
     if(!isset(self::$db_conn)) 
     { 
      $this->db_server = ModelBase::$DBSERVER; 
      $this->db_user = ModelBase::$DBUSER; 
      $this->db_password = ModelBase::$DBPASSWORD; 
      self::$db_conn = mysql_connect($this->db_server, $this->db_user, $this->db_password) or die(mysql_error(0)." Error handling database connection. "); 
      mysql_select_db(ModelBase::$DBNAME) or die("Couldn't select database."); 

      return self::$db_conn; 
     } 
    } 

    static function getConnection() 
    { 
     if (!isset(self::$db_conn)) 
     { 
      self::$db_conn = mysql_connect($this->db_server, $this->db_user, $this->db_password) or die(mysql_error(0)." Error handling database connection. "); 
      mysql_select_db(ModelBase::$DBNAME) or die("Couldn't select database."); 
     } 
     return self::$db_conn; 
    } 
} 

我有这个类继承了ModelBase。

<?php 
include("ModelBase.php"); 

>

<?php 
    class Lead extends ModelBase 
    { 
     public $id; 
     public $firstname; 
     public $lastname; 
     public $phone; 
     public $email; 
     public $notes; 

     public Lead() 
     { 

     } 

     public insert() 
     { 
      $con = ModelBase::getConnection(); 
      $query = "insert into test (id, firstname, lastname, phone, email, notes) values('','".$this->firstname."','".$this->lastname."','".$this->phone."','".$this->email."','".$this->notes."')"; 
      $res = mysql_query($query, $con) or die(mysql_error(0)." Error inserting ".$query); 

      return($res); 
     } 
    } 
?> 

最后我有一个测试文件：

include("Lead.php"); 

echo("Creating new lead"); 

$L = new Lead; 

echo("Inserting info"); 

$L->firstname = "Dev"; 
$L->lastname = "Test"; 
$L->phone = "8885552222"; 
$L->email = "dev@gmail.com"; 
$L->notes = "Test this screen."; 

echo($L->insert()); 

echo("Done."); 

，我发现了以下错误：

Parse error: syntax error, unexpected T_STRING, expecting T_VARIABLE in /var/www/html/joshk/test/Lead.php on line 15 

线15的public Lead()功能，我不能发现有什么不对。

Answer 1

您错过了function关键字。它必须是

class Lead extends ModelBase 
{ 
    public function Lead() 
    { 

    } 

    public function insert() 
    { 
     //.... 
    } 
} 

Answer 2

地址：

error_reporting(E_ALL); 
ini_set('display_errors', 'on'); 

测试页的顶部。

Answer 3

由于您使用PHP5，你应该使用PHP5 constructor syntax：

public function __construct() { ... } 

代替：

public Lead() { ... } 

（这是无论如何缺少function关键字。

Answer 4

并记住在你离开之前摆脱mysql错误报告生产。如果您的系统发现任何数据库信息出现错误，那就不好了。