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select first_name, last_name, uid from user where uid in (select uid2 from friend where uid1=me() and uid2 **not** in(SELECT user_id FROM like WHERE object_id={0}))
但是,这并不是不被Facebook所认可。你如何解决这个问题? 如果没有,你会得到喜欢的东西的所有朋友的列表fql选择不喜欢特定Facebook项目的朋友