2013-03-27 56 views
3

下面的连接在Access中工作,但我需要添加第四个连接。使用多个左连接的MS Access SQL

FROM ((Agents 
LEFT JOIN Resignation_Pool ON Agents.PF = Resignation_Pool.PF) 
LEFT JOIN Teams    ON Agents.Team = Teams.ID) 
LEFT JOIN Skills    ON Agents.PF = Skills.PF 

当我添加第四个连接时,它不起作用。我知道Access对括号很奇怪,但我认为我有他们属于他们的地方。查询只会永远运行(它不应该长时间运行),我最终取消它。有什么建议么?

FROM (((Agents 
LEFT JOIN Resignation_Pool ON Agents.PF = Resignation_Pool.PF) 
LEFT JOIN Teams    ON Agents.Team = Teams.ID) 
LEFT JOIN Skills    ON Agents.PF = Skills.PF) 
LEFT JOIN OneMore    ON Agents.OM = OneMore.OM 

这是代码的作品 - 我的实际查询,而不是一个我发现看起来相似。

SELECT DISTINCT A02.PID, A02.PS, A02.PN, A02.PM, C01.RC, C01.IC, C01.RD 
INTO AutoCR 
FROM ((02_CorrectResults A02 
LEFT OUTER JOIN dbo_pol_PGI C01 
    ON (A02.PID = C01.PID and C01.PS = '999' and C01.PEDate >= #04/01/2012#)) 
LEFT OUTER JOIN dbo_pol_IL C02 
    ON C01.PID = C02.PID) 
LEFT OUTER JOIN dbo_pol_UN C03 
    ON C02.ILID = C03.ILID 

我添加另一个连接,这是行不通的。我尝试使用内部连接,而不是Access。

SELECT DISTINCT A02.PID 
, A02.PS 
, A02.PN 
, A02.PM 
, C01.RC 
, C01.IC 
, C01.RD 
, C04.CCode 
, C04.PCode 
, C04.CForm, 
INTO AutoCR 
FROM (((02_CorrectResults A02 
LEFT OUTER JOIN dbo_rol_PGI C01 
    ON (A02.PID = C01.PID and C01.PS = '999' and C01.PEDate >= #04/01/2012#)) 
LEFT OUTER JOIN dbo_rol_IL C02 
    ON C01.PID = C02.PID) 
LEFT OUTER JOIN dbo_rol_UN C03 
    ON C02.ILID = C03.ILID) 
LEFT OUTER JOIN dbo_rol_HO C04 
    ON C03.UnID = C04.UnID 
+0

当你删除括号的时候会发生什么? 你可以显示整个查询吗? – Ogelami 2013-03-27 10:11:39

+2

使用设计器 – mcalex 2013-03-27 10:11:45

+0

设计器给出错误Microsoft Access无法在设计视图中表示联接表达式。 – Tracy 2013-03-27 11:36:13

回答

4

您的查询中有一个追踪,。去掉它。

SELECT DISTINCT A02.PID 
, A02.PS 
, A02.PN 
, A02.PM 
, C01.RC 
, C01.IC 
, C01.RD 
, C04.CCode 
, C04.PCode 
, C04.CForm, <--- this was the problem 
INTO AutoCR 
FROM (((02_CorrectResults A02 
LEFT OUTER JOIN dbo_rol_PGI C01 
    ON (A02.PID = C01.PID and C01.PS = '999' and C01.PEDate >= #04/01/2012#)) 
LEFT OUTER JOIN dbo_rol_IL C02 
    ON C01.PID = C02.PID) 
LEFT OUTER JOIN dbo_rol_UN C03 
    ON C02.ILID = C03.ILID) 
LEFT OUTER JOIN dbo_rol_HO C04 
    ON C03.UnID = C04.UnID