如何更换用分号逗号而不是引号内

Question

我有类似如下的CSV：

"blah blah, foo bar", 1, 454, ok, eng 
blah blah foo bar, 2, 21, ko, esp 
... 

我需要更换字段之间逗号到分号，所以我可以拆分正确CSV。但是，不要那些内心深处的人。

我需要或正则表达式o一个小脚本（python，groovy，bash ...）来解决这个问题。

Answer 1

考虑。演示：

from csv import reader, writer 
with open('input.csv') as inp, open('output.csv', 'w') as out: 
    writer(out, delimiter=';').writerows(reader(inp)) 

文件内容：

$ cat input.csv 
"blah blah, foo bar", 1, 454, ok, eng 
blah blah foo bar, 2, 21, ko, esp 
$ cat output.csv 
blah blah, foo bar; 1; 454; ok; eng 
blah blah foo bar; 2; 21; ko; esp 

Answer 2

import csv 

infile = open("inputfile.csv", "r") 
outfile = open("outputfile.csv", "w") 

csvReader = csv.reader(infile) 

for line in csvReader: 
    outfile.write(";".join(line) + "\n") 

infile.close() 
outfile.close() 

测试关于Python 2.7和3.5

输出上的例子：使用Python的csv模块

blah blah, foo bar; 1; 454; ok; eng 
blah blah foo bar; 2; 21; ko; esp