我正在尝试在两个链接的服务器上编写查询。已经设立具有适当的登录链接,我得到这个整理错误:如何在T-SQL中正确构造collate命令?
Cannot resolve the collation conflict between "SQL_Latin1_General_CP1_CI_AS" and "Latin1_General_CI_AS" in the equal to operation.
这是新的给我,但它看起来像一个字符集冲突,所以我用Google搜索,并发现了分页打印指令从而可以被添加到我的加入。但是我都试过
va ON V_ID1 = c1.strData COLLATE Latin1_General_CI_AS
和
va ON V_ID1 = c1.strData COLLATE SQL_Latin1_General_CP1_CI_AS
而且,无论似乎解决错误。我究竟做错了什么?
编辑:整个查询太大张贴,并期望人们过滤通过,但这里的相关位:
select
rel.intParentAttributeId as intItemId,
case va.type
when 'SM' then 120000000
when 'FB' then 110000000
when 'RO' then 100000000
when 'SP' then 90000000
when 'A' then 80000000
when 'D' then 70000000
when 'P' then 60000000
when 'SR' then 50000000
when 'FN' then 40000000
when 'RL' then 30000000
when 'VO' then 20000000
when 'RE' then 10000000
end
+
rel.intParentAttributeId
as fltStrength
from
AttributeMap ky
join Catalogue c1 on c1.intRowId=ky.intChildAttributeId and [email protected]
join
[SQLSERVERNAME].[SchemaName].dbo.VidAssc
va on V_ID1 COLLATE SQL_Latin1_General_CP1_CI_AS = c1.strData COLLATE SQL_Latin1_General_CP1_CI_AS
join Catalogue c2 on c2.strData=V_ID2 and [email protected]
join AttributeMap rel on rel.intChildAttributeId = c2.intRowId
join @tmpSeeds s on s.intItemId = ky.intParentAttributeId
group by rel.intParentAttributeId,va.Type
)sqi
干杯, 马特
你能请张贴整个查询?那里可能有些东西你认为是理所当然的。 – 2011-04-11 16:30:40