Django简单发布请求不起作用

Question

我是Django的新手，尝试构建简单的网页。我试图发布请求，但没有值插入到数据库中。我希望问题应该在views.py forms.is_valid（）由于没有日志记录在此行后。请帮助

模型。 PY

from django.db import models 
from django.contrib.auth.models import User 
from django.db.models import Q 
from django.forms import ModelForm 
from django import forms 
# Create your models here. 

class aws_cred(models.Model): 
    aws_access_user_id = models.ForeignKey(User,null=False,related_name="aws_acc_user") 
    access_key = models.CharField(max_length=300) 
    secret_key = models.CharField(max_length=300) 



class aws(ModelForm): 
    class Meta: 
     model = aws_cred 
     fields = ['access_key','secret_key','aws_access_user_id'] 

views.py

from django.shortcuts import render_to_response,HttpResponseRedirect,render,redirect,reverse 
from django.contrib.auth.decorators import login_required 
from django.template import RequestContext 
from s3comp.models import aws_cred,aws 
import logging 

@login_required 
def fileinput(req): 
    logging.basicConfig(filename='log_filename.txt',level=logging.DEBUG, format='%(asctime)s - %(levelname)s - %(message)s') 
    if req.method == 'POST': 
     form = aws(req.POST) 
     logging.debug(form) 
     try: 
      logging.debug('step 4') 
      if form.is_valid(): 
       logging.debug('step 5') 
       access_key_val = req.POST.get('access key','') 
       secret_key_val = req.POST.get('secret key','') 
       aws_access_user_id_val = req.POST.get('aws access user id', '') 
       logging.debug(access_key_val+" " +secret_key_val+" " +aws_access_user_id_val) 
       cred_obj = aws(access_key = access_key_val,secret_key =secret_key_val,aws_access_user_id = aws_access_user_id_val) 
       cred_obj.save() 
       return HttpResponseRedirect(reverse('s3comp:fileinput')) 
     except Exception as e: 
      logging.debug(e) 
    else: 
     form = aws() 

    return render(req,'s3comp/fileinput.html',{'form':form}) 

HTML文件

<form action="{% url 'fileinput_home' %}" method="post"> 
    {% csrf_token %} 
     <p><label for="Aws access user id">User:</label><input type="text" name="Aws access user id" value={{ user.get_username }}/></p> 
     <p><label for="Access Key">Access Key:</label><input type="text" name="Access Key"/></p> 
     <p><label for="Secret Key">Secret Key:</label><input type="text" name="Secret Key"/></p> 
    <input type="submit" value="Submit"> 
</form> 

Answer 1

您正在使用的模板和看法错名字的属性值，所以更新根据下面的代码

<form action="{% url 'fileinput_home' %}" method="post"> 
    {% csrf_token %} 
     <p><label for="Aws access user id">User:</label><input type="text" name="aws_access_user_id" value={{ user.get_username }}/></p> 
     <p><label for="Access Key">Access Key:</label><input type="text" name="access_key"/></p> 
     <p><label for="Secret Key">Secret Key:</label><input type="text" name="secret_key"/></p> 
    <input type="submit" value="Submit"> 
</form> 

Views.py

access_key_val = req.POST.get('access_key','') 
secret_key_val = req.POST.get('secret_key','') 
aws_access_user_id_val = req.POST.get('aws_access_user_id', '')