T-SQL：如何对特定列上的行进行分组？

Question

SELECT DISTINCT 
     IncreasmentAmount, 
     Name, 
     regionid 
FROM   Pricing.GroupOfRegions 
WHERE regionid in (6,7) 

此语句产生这样的结果：

12.80 AB 6 
13.00 ABC 6 
15.00 AC 6 
12.80 AB 7 
13.00 ABC 7 

我想添加多个条件，其中IncreasmentAmount s为相等。这将导致具有相同IncreasmentAmount的行：

12.80 AB 6 
12.80 AB 7 

如何修改查询以生成我想要的结果？

Answer 1

我认为这可以帮助你。

SELECT DISTINCT IncreasmentAmount, Name, regionid, count(*) 
FROM Pricing.GroupOfRegions 
where regionid in (6,7) 
group by IncreasmentAmount, Name, regionid 
having count(*) > 1 

Answer 2

例如

create table #bla(IncreasmentAmount decimal(16,2),Name varchar(40),regionid int) 
insert #bla values(12.80, 'AB', 6) 
insert #bla values(13.00, 'ABC', 6) 
insert #bla values(15.00, 'AC', 6) 
insert #bla values(12.80, 'AB', 7) 
insert #bla values(13.00, 'ABC', 7) 

这里是做的一个方式，

--group also by name 
select b.* from(
SELECT IncreasmentAmount, Name 
FROM   #bla 
where regionid in (6,7) 
group by IncreasmentAmount, Name 
having count(*) > 1) as a 
join #bla b on a.IncreasmentAmount = b.IncreasmentAmount 
and a.Name = b.Name 
where b.regionid in (6,7) 

或

-- don not group by name 
select b.* from(
SELECT IncreasmentAmount 
FROM   #bla 
where regionid in (6,7) 
group by IncreasmentAmount 
having count(*) > 1) as a 
join #bla b on a.IncreasmentAmount = b.IncreasmentAmount 
where b.regionid in (6,7) 

Answer 3

如果你的意思是你需要只显示行为其第一列等于其他行，那么我恐怕哟日子会把你必须做一个嵌套查询是这样的：

SELECT DISTINCT IncreasmentAmount, Name, regionid 
FROM   Pricing.GroupOfRegions 

where regionid in (6,7) 
and IncreasmentAmount IN (select IncreasmentAmount 
          from Pricing.GroupOfRegions 
          group by IncreasmentAmount 
          having COUNT(*) > 1)