转换CSV到键控JSON

Question

我有一个包含类似下面的数据带列标题的CSV文件

100271311,90445XXXX,Active 
100271400,99456XXXX,Cancelled 
100271552,94280XXXX,Pending 

我想上面的转换为PHP JSON输出像下面

{ 
    "100271311": { 
     "FIELD2": "90445XXXX", 
     "FIELD3": "Active" 
    }, 
    "100271400": { 
     "FIELD2": "99456XXXX", 
     "FIELD3": "Cancelled" 
    }, 
    "100271552": { 
     "FIELD2": "94280XXXX", 
     "FIELD3": "Pending" 
    } 
} 

请帮助

Answer 1

你可以试试：

$file = file('pathtoyour/file.csv'); 
    $json = []; 
    foreach ($file as $key => $row) { 
    $cols = explode(',', $row); 
    $json[trim($cols[0])] = [ 
     'FIELD2' => trim($cols[1]), 
     'FIELD3' => trim($cols[2]), 
    ]; 
    } 
    die(json_encode($json)); 

Answer 2

您可以试试这个：

$file = "csvfile.csv"; 
$csv = file_get_contents($file); 
$array = array_map("str_getcsv", explode("\n", $csv)); 
$json = json_encode($array); 
print_r($json); 

注： str_getcsv为CSV格式的字段解析字符串输入，并返回包含读取字段的数组。

Answer 3

使用file，explode和json_encode功能的解决方案：

$lines = file("./data/test.csv"); // change with your actual file path 
$result = []; 

foreach ($lines as $line) { 
    list($k, $f2, $f3) = explode(',', $line); 
    $result[$k] = ['FIELD2' => $f2, 'FIELD3' => trim($f3)]; 
} 

print_r(json_encode($result, JSON_PRETTY_PRINT)); 

输出：

{ 
    "100271311": { 
     "FIELD2": "90445XXXX", 
     "FIELD3": "Active" 
    }, 
    "100271400": { 
     "FIELD2": "99456XXXX", 
     "FIELD3": "Cancelled" 
    }, 
    "100271552": { 
     "FIELD2": "94280XXXX", 
     "FIELD3": "Pending" 
    } 
}