2012-04-03 98 views
0

我创建了一个播放应用程序,并有一些模型。其中一个包含一个对象设置,但JPA不能创建表...JPA @ElementCollection播放框架错误

package models; 

import java.util.ArrayList; 
import java.util.Date; 
import java.util.Map; 
import java.util.Set; 

import javax.persistence.ElementCollection; 
import javax.persistence.Entity; 
import javax.persistence.Table; 

import play.db.jpa.Model; 

@Entity 
public class Receipt extends Model { 

    @ElementCollection 
    Set<Serving> servings; 
    DiningTable table; 

    public Receipt(Set<Serving> servings, DiningTable table) { 
     super(); 
     this.servings = servings; 
     this.table = table; 
    } 

} 

和错误是

 
21:20:47,323 INFO ~ Listening for HTTP on port 9000 (Waiting a first request to start) ... 
21:20:51,935 INFO ~ Connected to jdbc:mysql://localhost/rms_?>useUnicode=yes&characterEncoding=UTF-8&connectionCollation=utf8_general_ci 
21:20:52,827 ERROR ~ Unsuccessful: create table Receipt (id bigint not null auto_increment, >table tinyblob, primary key (id)) ENGINE=InnoDB DEFAULT CHARSET=utf8 
21:20:52,827 ERROR ~ You have an error in your SQL syntax; check the manual that >corresponds to your MySQL server version for the right syntax to use near 'table tinyblob, >primary key (id)) ENGINE=InnoDB DEFAULT CHARSET=utf8' at line 1 
21:20:53,183 ERROR ~ Unsuccessful: alter table Receipt_Serving add index FKB18778C559F3AF16 >(Receipt_id), add constraint FKB18778C559F3AF16 foreign key (Receipt_id) references Receipt >(id) 
21:20:53,183 ERROR ~ Can't create table 'rms_.#sql-731_f2' (errno: 150) 
21:20:53,414 INFO ~ Application 'rms' is now started ! 

我怎样才能解决这个问题?

回答

1

table是保留关键字。尝试使用不同columname通过改变字段名或通过添加:

@Column(name="diningTable") 

而且,我怀疑你想DiningTable成为一个实体,而不是存储为字节码(TINYBLOB)。如果是的话,你应该添加一些关系注释。

+0

哪些关系注释?像manytoone或manytomany? – 2012-04-03 19:05:49

+0

由于您没有收据上的表格集合,它将是\ @ManyToOne。你确定你想在你的服务中使用\ @ElementCollection吗?它是\ @Embedable,你不想单独查询?也许你应该考虑\ @OneToMany? – barsju 2012-04-03 19:16:00

+1

http://en.wikibooks.org/wiki/Java_Persistence/ElementCollection – barsju 2012-04-03 19:17:02