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我有一张收集客户付款的表。我想从前3名客户那里得到每个客户的付款。同一张表中的MySQL子查询
下面的查询获得每个客户每天每小时的总付款。下面
SELECT
hour(received) as hr,
login,
count(*) as total
FROM
payment
WHERE
received >= date("2011-02-24")
AND
received <date("2011-02-25")
AND
PAYMENT_BATCH_FILE_ID is null
GROUP BY
hr,
client_id
ORDER BY
hr,
total DESC
查询获得前3名的客户端为每一个客户在一个小时内
SELECT
hour(received) as hr,
login,
count(*) as total
FROM
payment
WHERE
received >=date("2011-02-24")
AND
received < date("2011-02-25")
AND
PAYMENT_BATCH_FILE_ID is null
AND
hour(received)="3"
GROUP BY
hr,
client_id
ORDER BY
hr,
total DESC
LIMIT 3
如何将两者结合起来的查询获得前3名的客户,使每个小时支付?
谢谢。
有点失去了你在找什么...你想要前3名的客户吗?或者每天每小时(72个结果)还是?还有点在“一小时内让每位客户获得前三名客户”中输掉? – CarpeNoctumDC 2011-03-09 08:44:25
我想在一天中的每个小时内获得3位客户的信息 – muhdazmilug 2011-03-10 00:36:04