排序3个人的年龄

Question

/* to find the age of individuals according to youngest to oldest */ 

#include <stdio.h> 

int main(void){ 
    int age1, age2, age3, youngest, middle, oldest; 

    printf ("Enter the age of the first individual: "); 
    scanf ("%d", &age1); 
    printf ("Enter the age of the second individual: "); 
    scanf ("%d", &age2); 
    printf ("Enter the age of the third individual: "); 
    scanf ("%d", &age3); 

    if ((age1 == age2) && (age2 == age3)){ 
     printf("All individuals have the same age of %d", &age2); 
    } 

    else (age1 != age2) && (age1 != age3) && (age2 != age3);{ 
     youngest = age1; 

     if (age1 > age2) 
      youngest = age2; 
     if (age2 > age3) 
      youngest = age3; 

     middle = age1; 

     if (age1 > age2) 
      middle = age2; 
     if (age2 < age3) 
      middle = age2; 

     oldest = age1; 

     if (age1 < age2) 
      oldest = age2; 
     if (age2 < age3) 
      oldest = age3; 

     printf("%d is the youngest.\n", youngest); 
     printf("%d is the middle.\n", middle); 
     printf("%d is the oldest.\n", oldest); 
    } 

    return 0; 

} 

嗨我改变了我的代码，但显示仍然显示一个奇怪的数字，当我输入每个人的相同年龄。我如何做到这一点，如果每个人都有同样的年龄，那么只有说所有人都有相同年龄的线。请帮助我作为它的分级任务，并且即时遇到这个问题

所有人的年龄都是63567321是最年轻的。 1是中间的。 1是最古老的。

Answer 1

三个主要问题：

1. 当平等的年龄，你是路过的指针整数整数本身printf()
2. else statment没有一个'如果”
3. 压痕 - 不会影响执行，但对帮助您更容易在代码中发现问题至关重要

正确的代码：

/* to find the age of individuals according to youngest to oldest */ 

#include <stdio.h> 

int main(void) 

{ 
    int age1, age2, age3, youngest, middle, oldest; 
    printf ("Enter the age of the first individual: "); 
    scanf ("%d", &age1); 
    printf ("Enter the age of the second individual: "); 
    scanf ("%d", &age2); 
    printf ("Enter the age of the third individual: "); 
    scanf ("%d", &age3); 

    if ((age1 == age2) && (age2 == age3)) 
    { 
    printf("All individuals have the same age of %d", age2); 
    } 

    else if ((age1 != age2) && (age1 != age3) && (age2 != age3)) 
    { 
     youngest = age1; 

     if (age1 > age2) 
     youngest = age2; 
     if (age2 > age3) 
     youngest = age3; 

     middle = age1; 

     if (age1 > age2) 
     middle = age2; 
     if (age2 < age3) 
     middle = age2; 

     oldest = age1; 

     if (age1 < age2) 
     oldest = age2; 
     if (age2 < age3) 
     oldest = age3; 

     printf("%d is the youngest.\n", youngest); 
     printf("%d is the middle.\n", middle); 
     printf("%d is the oldest.\n", oldest); 
    } 

    return 0; 

} 

- 编辑

请注意，在上述方案中，如果两个年龄都是平等的，最古老和最年轻的年龄不打印。要解决这个问题，我会删除else的if条件，并在打印中间值之前包含一个检查。新别的statment：

else 
    { 
     youngest = age1; 

     if (age1 > age2) 
     youngest = age2; 
     if (age2 > age3) 
     youngest = age3; 

     middle = age1; 

     if (age1 > age2) 
     middle = age2; 
     if (age2 < age3) 
     middle = age2; 

     oldest = age1; 

     if (age1 < age2) 
     oldest = age2; 
     if (age2 < age3) 
     oldest = age3; 

     printf("%d is the youngest.\n", youngest); 

     // If two ages are equivalent, do not print middle 
     if ((age1 != age2) && (age1 != age3) && (age2 != age3)) 
      printf("%d is the middle.\n", middle); 

     printf("%d is the oldest.\n", oldest); 
    } 

免责声明：虽然我已经给出了上述解决方案，以保持原有的代码，我宁愿在下面的方式更通用的方法：

1. 创建排序的方法整数数组：sort(int *array, int size)
2. 读输入年龄为整数数组：int ages[3]
3. 传千古的排序功能：sort(ages, 3);
从排序的阵列10个
4. 打印结果：ages[0]，ages[1]，ages[2]

这样的代码的方式更具可读性和可重用..

Answer 2

你为什么不这样做

if (age1>age2 && age1>age3) { 
    oldest=age1; 
    if (age2>age3) 
     middle = age2; 
     youngest=age3; 
    } else { 
     middle = age3; 
     youngest=age2; 
    } 
} else if (age2>age3) { 
    oldest=age2; 
    if (age1>age3) 
     middle = age1; 
     youngest=age3; 
    } else { 
     middle = age3; 
     youngest=age1; 
    } 
} else { 
    oldest=age3; 
    if (age2>age1) 
     middle = age2; 
     youngest=age1; 
    } else { 
     middle = age1; 
     youngest=age2; 
    } 
}