2010-07-23 60 views

回答

2

我很惊讶没有人有建议BitConverter呢。假设你已经在独立变量的三个字节:

var data = new byte[] 
{ 
    byte0 & 0x80 == 0 ? 0 : 0xFF, byte0, byte1, byte2 
}; 
return BitConverter.ToInt32(data, 0); 

或者:

var data = new byte[] { byte0, byte1, byte2, 0x00 }; 
return BitConverter.ToInt32(data, 0) >> 8; 
+1

如果你想让它跨不同字节序架构正常工作,那么你需要手动测试'BitConverter.IsLittleEndian'并相应地调整你的'data'排列的顺序。这比首先手动完成手动操作要复杂得多。 – LukeH 2010-07-24 00:34:27

+0

好,卢克。 XBox(也可能是Mono)支持大端架构。 – 2010-07-24 00:42:53

+0

非常感谢您的解释! – Evan 2010-07-24 00:48:36

0
int converted = ((bytes[2] << 24) | (bytes[1] << 16) | (bytes[0] << 8)) >> 8; 
0

我被Bitconverter的小尾数性质烧一次。 下面是一个替代方法: PS:格式不是小端,它的其他方式与MSB第一!还我试图格式化输出比特码的手动,但未能

输出:

=======测试24位的Int32(MSB首先/左)======= 预期: 8388607 Bit24ToInt32测试:8388607 预计:-1 Bit24ToInt32测试:-1 预计:-8388607 Bit24ToInt32测试:-8388607 预计:6147053 Bit24ToInt32测试:6147053

预计:-6147053 Bit24ToInt32测试:-6147053

=======测试16位到Int32(MSB First/Left)= ====== 预计:32767 Bit16ToInt32测试:32767 预计:-1 Bit16ToInt32测试:-1 预计:-32767 Bit16ToInt32测试:-32767 预期:24045 Bit16ToInt32测试:24045

预计:-24045 Bit16ToInt32测试:-24045

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks; 

namespace BitExperiments 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      //Test 16bit to Int32(MSB First/Left) 
      Console.WriteLine("=======Test 24 bit to Int32 (MSB First/Left)======="); 
      Dictionary<int,byte[]> cases = new Dictionary<int,byte[]>(); 
      byte[] bytearr; 
      int expectedResult; 

      bytearr = new byte[] { 0x7F, 0xFF, 0xFF }; 
      expectedResult= 8388607;//Max 
      cases.Add(expectedResult,bytearr); 

      bytearr = new byte[] { 0xFF, 0xFF, 0xFF }; 
      expectedResult = (-1);//Mid 
      cases.Add(expectedResult,bytearr); 

      bytearr = new byte[] { 0x80, 0x00, 0x01 }; 
      expectedResult = (-8388607);//Min 
      cases.Add(expectedResult,bytearr); 

      bytearr = new byte[] { 0x5D, 0xCB, 0xED }; 
      expectedResult= 6147053;//Random 
      cases.Add(expectedResult,bytearr); 

      bytearr = new byte[] { 0xA2, 0x34, 0x13 }; 
      expectedResult= (-6147053);//Random inverted 
      cases.Add(expectedResult,bytearr); 

      foreach (var value in cases) 
      { 
       Console.WriteLine("Expected: {0} \t\t Bit24ToInt32 Test: {1}", value.Key, Bit24ToInt32(value.Value)); 
      } 

      Console.WriteLine("==================================================="); 
      Console.WriteLine(); 
      //Test 16bit to Int32(MSB First/Left) 
      Console.WriteLine("=======Test 16 bit to Int32 (MSB First/Left)======="); 
      cases.Clear(); 

      bytearr = new byte[] { 0x7F, 0xFF }; 
      expectedResult = 32767;//Max 
      cases.Add(expectedResult, bytearr); 

      bytearr = new byte[] { 0xFF, 0xFF }; 
      expectedResult = (-1);//Mid 
      cases.Add(expectedResult, bytearr); 

      bytearr = new byte[] { 0x80, 0x01 }; 
      expectedResult = (-32767);//Min 
      cases.Add(expectedResult, bytearr); 

      bytearr = new byte[] { 0x5D, 0xED }; 
      expectedResult = 24045;//Random 
      cases.Add(expectedResult, bytearr); 

      bytearr = new byte[] { 0xA2, 0x13 }; 
      expectedResult = (-24045);//Random inverted 
      cases.Add(expectedResult, bytearr); 

      foreach (var value in cases) 
      { 
       Console.WriteLine("Expected: {0} \t\t Bit16ToInt32 Test: {1}", value.Key, Bit16ToInt32(value.Value)); 
      } 
      Console.WriteLine("==================================================="); 
      Console.ReadLine(); 
     } 
     private static int Bit24ToInt32(byte[] byteArray) 
     { 
      int result = ( 
       ((0xFF & byteArray[0]) << 16) | 
       ((0xFF & byteArray[1]) << 8) | 
       (0xFF & byteArray[2]) 
       ); 
      if ((result & 0x00800000) > 0) 
      { 
       result = (int)((uint)result|(uint)0xFF000000); 
      } 
      else 
      { 
       result = (int)((uint)result & (uint)0x00FFFFFF); 
      } 
      return result; 
     } 

     private static int Bit16ToInt32(byte[] byteArray) { 
      int result = (
       ((0xFF & byteArray[0]) << 8) | 
       (0xFF & byteArray[1]) 
      ); 
      if ((result & 0x00008000) > 0) { 
        result = (int) ((uint) result | (uint) 0xFFFF0000); 

      } else { 
        result = (int) ((uint) result & (uint) 0x0000FFFF); 
      } 
      return result; 
      }   
    } 
}