0
当使用下面的查询时,我插入了product_id,并且还希望为所有插入的product_id设置字段category_id = 4。这是我的代码插入产品。从另一个表中插入Mysql查询
INSERT INTO lc_products_to_categories
(product_id)
SELECT product_id
FROM lc_products_info
where name like '%awesome product%'
如何使用单个查询更新category_id?
只是选择这样NSERT INTO lc_products_to_categories (产品,CATEGORY_ID)PRODUCT_ID,4 FROM lc_products_info 恒定其中name LIKE '%真棒产物%' – JYoThI