2017-07-06 56 views
0

当使用下面的查询时,我插入了product_id,并且还希望为所有插入的product_id设置字段category_id = 4。这是我的代码插入产品。从另一个表中插入Mysql查询

INSERT INTO lc_products_to_categories 
(product_id) 
SELECT product_id 
FROM lc_products_info 
where name like '%awesome product%' 

如何使用单个查询更新category_id?

+0

只是选择这样NSERT INTO lc_products_to_categories (产品,CATEGORY_ID)PRODUCT_ID,4 FROM lc_products_info 恒定其中name LIKE '%真棒产物%' – JYoThI

回答

0
INSERT INTO lc_products_to_categories 
(product_id, category_id) 
SELECT product_id, 4 
FROM lc_products_info 
where name like '%awesome product%'