我有一个名为'questions'的数组,我有一个与它关联的对象变量,它也是一个名为'choices'的数组。数组对象
var questions = [
{
question: "What type of business do you run?",
choices: ['Business to Business - Provide products and/or services to other
businesses', 'Business to Business to Consumer - Provide products
and/or services to other businesses for consumers',
'Business to Consumer - Provide products and/or services to
consumers'],
choiceValues: [1, 2, 3],
}
我想在for循环中使用“选择”的长度,如下所示。这句法正确吗?我似乎无法增加“点数”变量。
function displayScore()
{
var score = $('<p>',{id: 'question'});
var points = 0;
for (var i = 0; i < selections.length; i++)
{
for (var j = 0; j < questions[i].choices.length; j++)
{
if (selections[i] === questions[i].choices[j])
{
points = points + questions[i].choiceValues[j];
}
}
}
score.append('You got ' + points + ' points!');
return score;
}
'选择'的一个例子是:[0,4,0,1,0,1,0,1]。
你已经验证了什么'的问题[I] .choices [j]'是?它与您所期望的相符吗?另外,什么是“选择”? – Carcigenicate
@Carcigenicate'selections'是一个包含用户对问题的答案的数组。我使用inner for循环来检查他们的答案匹配列表中哪个答案。根据匹配的答案,分配一定数量的点,由'choiceValues'定义。 –
提供'选择'的示例 – luisenrike