以编程方式获取ASP.NET MVC应用程序的控制器地址

Question

说我想从我的MVC应用程序发送包含链接回到项目的电子邮件。

所以我想在我的控制器是这样的：

string link = "www.mysite/mycontroller/itemdetails/23"; 

我可以检索这个编程所以它适用于任何服务器/配置我碰巧坚持下去吗？

如

string link = GetCurrentActionRoute() + "23"; 

Answer 1

public ActionResult Index() 
{ 
    string link = Url.Action(
     (string)RouteData.Values["action"], 
     (string)RouteData.Values["controller"], 
     new { id = "23" }, 
     Request.Url.Scheme 
    ); 
    // TODO: do something with the generated link 
    return View(); 
} 

Answer 2

我用从我的控制器类下面的扩展方法来生成链接到各种动作。

例子：

string link = this.Action("Play"); 
string fullLink = this.FullUrlAction("Play", new { id = 1 }); 

方法：

/// <summary> 
/// Helper Extensions to the Controller class. 
/// </summary> 
public static class ControllerExtensions 
{ 
    /// <summary> 
    /// Get an action link for a controller. 
    /// </summary> 
    /// <param name="controller">Controller instance.</param> 
    /// <param name="action">Action to provide the link for.</param> 
    /// <returns>Link Url for the Action.</returns> 
    public static string Action(this Controller controller, string action) 
    { 
     RouteValueDictionary rvd = new RouteValueDictionary 
             { 
              { "controller", controller.GetType().Name }, 
              { "action", action } 
             }; 

     return RouteTable.Routes.GetVirtualPath(controller.ControllerContext.RequestContext, rvd).VirtualPath; 
    } 

    /// <summary> 
    /// Get an action link for a controller. 
    /// </summary> 
    /// <param name="controller">Controller instance.</param> 
    /// <param name="action">Action Name.</param> 
    /// <param name="parameters">Action Parameters.</param> 
    /// <returns>Link Url for the action with parameters.</returns> 
    public static string Action(this Controller controller, string action, object parameters) 
    { 
     string controllerName = controller.GetType().Name; 
     if (controllerName.EndsWith("Controller")) 
     { 
      controllerName = controllerName.Substring(0, controllerName.Length - 10); 
     } 

     return controller.Action(controllerName, action, parameters); 
    } 

    /// <summary> 
    /// Get an action link for a controller. 
    /// </summary> 
    /// <param name="controller">Controller instance.</param> 
    /// <param name="targetController">Target controller for action.</param> 
    /// <param name="action">Action Name.</param> 
    /// <param name="parameters">Action Parameters.</param> 
    /// <returns>Link Url for the action on the given controller.</returns> 
    public static string Action(this Controller controller, string targetController, string action, object parameters) 
    { 
     RouteValueDictionary rvd = new RouteValueDictionary(parameters) 
             { 
              { "controller", targetController }, 
              { "action", action } 
             }; 

     return RouteTable.Routes.GetVirtualPath(controller.ControllerContext.RequestContext, rvd).VirtualPath; 
    } 

    /// <summary> 
    /// Get a fully qualified action link for a controller. 
    /// </summary> 
    /// <param name="controller">Controller instance.</param> 
    /// <param name="action">Action Name.</param> 
    /// <param name="parameters">Action Parameters.</param> 
    /// <param name="requestUrl">Current request URI.</param> 
    /// <returns>Fully qualified Link Url.</returns> 
    public static string FullUrlAction(this Controller controller, string action, object parameters, Uri requestUrl) 
    { 
     string controllerName = controller.GetType().Name; 
     if (controllerName.EndsWith("Controller")) 
     { 
      controllerName = controllerName.Substring(0, controllerName.Length - 10); 
     } 

     return controller.FullUrlAction(controllerName, action, parameters, requestUrl); 
    } 

    /// <summary> 
    /// Get a fully qualified action link for a controller. 
    /// </summary> 
    /// <param name="controller">Controller instance.</param> 
    /// <param name="targetController">Target controller for action.</param> 
    /// <param name="action">Action Name.</param> 
    /// <param name="parameters">Action Parameters.</param> 
    /// <param name="requestUrl">Current request URI.</param> 
    /// <returns>Fully Qualified Link Url.</returns> 
    public static string FullUrlAction(this Controller controller, string targetController, string action, object parameters, Uri requestUrl) 
    { 
     string testUrl = VirtualPathUtility.ToAbsolute(controller.Action(targetController, action, parameters)); 
     return new Uri(requestUrl, testUrl).ToString(); 
    } 
} 

Answer 3

如果该链接将指向同一位置的应用程序，你可以考虑使用Url.Action（。 ..）及其过载。

例如，

string actionRoute = Url.Action("action method name","controller name"); 

如果你想获得完整的路径，你可以使用：

string domainRoute = HttpContext.Request.Url.AbsolutePath; 

，然后与串联的ID。