2013-01-02 65 views
0

使用蛋糕acl我想设置登录用户的权限。我有这样的登录功能:acl权限

if ($user = $this->Auth->user()) { 
    CakeLog::write('debug', 'this->Auth->user'); 
    //debug($user['User']); 
    $userGroup = $this->User->Group->findById($user['User']['group_id']); 
    $aro = $this->Acl->Aro->find('first', array(
     'conditions' => array(
      'Aro.model' => 'Group', 
      'Aro.foreign_key' => $this->_user['User']['group_id'], 
     ), 
    )); 
    $acos = $this->Acl->Aco->children(); 
    foreach ($acos as $aco) { 
    $permission = $this->Acl->Aro->Permission->find('first', array(
     'conditions' => array(
      'Permission.aro_id' => $aro['Aro']['id'], 
      'Permission.aco_id' => $aco['Aco']['id'], 
     ), 
    )); 
    if (isset($permission['Permission']['id'])) { 
     if ($permission['Permission']['_create'] == 1 || 
      $permission['Permission']['_read'] == 1 || 
      $permission['Permission']['_update'] == 1 || 
      $permission['Permission']['_delete'] == 1) { 
       $this->Session->write(
        'Auth.Permissions.' . $permission['Aco']['alias'], true 
       ); 
       if (!empty($permission['Aco']['parent_id'])) { 
        $parentAco = $this->Acl->Aco->find('first', array(
         'conditions' => array(
          'id' => $permission['Aco']['parent_id'] 
         ) 
        )); 
        $this->Session->write(
         'Auth.Permissions.' . $permission['Aco']['alias'] 
         . '.' . $parentAco['Aco']['alias'], true 
        ); 
       } 
      } 
     } 
    } 
} 

我收到此错误:

未定义的属性:UsersController :: $ _用户[APP \控制器\ users_controller.php中,行82]

我可以用'$ this - > _ user ['User'] ['group_id']'来更改'$ this - > _ user ['User'] ['group_id']',这是否正确。如果不是我应该设置公共$ _user =?

感谢

+0

什么是第82行?所有的错误意味着你缺少类上的$ _user变量。 – jeremyharris

+0

这是行82'Aro.foreign_key'=> $ this - > _ user ['User'] ['group_id'],' – rstewart

+0

我可以设置_user变量,但是_user应该设置为什么?它是否与$ user ['User'] ['group_id']相同? – rstewart

回答

0

我换成$用户_user,它似乎是工作。

-1

,如果你需要验证用户的GROUP_ID您可以拨打

AuthComponent::user('group_id');