使用“函数getline”使用数组

Question

我有这样的代码：

#include <iostream> 
#include <cstring>  // for the strlen() function 

int main() 
{ 
    using namespace std; 

    const int Size = 15; 
    static char name1[Size];     //empty array 
    static char name2[Size] = "Jacob";  //initialized array 

    cout << "Howdy! I'm " << name2; 
    cout << "! What's your name?" << endl; 
    cin >> name1; 
    cout << "Well, " << name1 << ", your name has "; 
    cout << strlen(name1) << " letters and is stored" << endl; 
    cout << "in an array of " << sizeof(name1) << " bytes" << endl; 
    cout << "Your intitial is " << name1[0] << "." << endl; 
    name2[3] = '\0'; 

    cout << "Here are the first 3 characters of my name: "; 
    cout << name2 << endl; 

    cin.get(); 
    cin.get(); 

    return 0; 
} 

的问题

在这段代码中，唯一的问题是，如果你用空格输入你的名字，它会跳过姓氏之后的空间。 getline（）方法可以解决这个问题，但我似乎无法完成。解决这个问题甚至可能有更好的方法。总而言之，我希望能够在开始提示时输入名字和姓氏（一个全名）。

程序

程序简单地提示，使用输入他们的名字，然后输出该用户名，与以字节为单位的大小和用户的姓名的前三个字符沿。

Answer 1

使用函数getline方法是这样的：

cout << "! What's your name?" << endl; 
cin.getline(name1, sizeof(name1)); 
cout << "Well, " << name1 << ", your name has "; 

要计算非空格字符：

#include <iostream> 
#include <cstring>  // for the strlen() function 
#include <algorithm> 
int main() 
{ 
    using namespace std; 

    const int Size = 15; 
    static char name1[Size];     //empty array 
    static char name2[Size] = "Jacob";  //initialized array 
    cout << "Howdy! I'm " << name2; 
    cout << "! What's your name?" << endl; 
    cin.getline(name1, sizeof(name1)); 
    cout << "Well, " << name1 << ", your name has "; 
    int sz_nospace = count_if(name1, name1 + strlen(name1), 
      [](char c){return c!=' ';}); 
    cout << sz_nospace << " letters and is stored" << endl; 
    cout << "in an array of " << sizeof(name1) << " bytes" << endl; 
    cout << "Your intitial is " << name1[0] << "." << endl; 
    name2[3] = '\0'; 

    cout << "Here are the first 3 characters of my name: "; 
    cout << name2 << endl; 

    return 0; 
}