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我有和可观察,如果它由函数返回,它永远不会发送onNext,但如果我在它返回它的函数中订阅它,onNext被调用。从函数返回的Observable永远不会发送onNext
class InfoViewModel {
func refreshPushToken() {
PushNotificationService.sharedInstance.pushToken!
.flatMapLatest { (pushToken: String) -> Observable<Result<User>> in
return UserService.registerPushToken(pushToken)
}
.subscribe { (event) in
print(event)
}
.addDisposableTo(disposeBag)
}
}
struct UserService {
....
static func registerPushToken(_ pushToken: String) -> Observable<Result<User>> {
...
return self.postUser(user: user)
}
static fileprivate func postUser(user: User) -> Observable<Result<User>> {
let rxProvider: RxMoyaProvider<Backend> = RxMoyaProvider<Backend>(endpointClosure: Backend.endpointClosure)
return rxProvider.request(Backend.register(user: user))
.mapObject(type: User.self)
.map({ (user: User) -> Result<User> in
LogService.log(level: .debug, action: "postUser", message: "Posted user with success", parameters: ["user": user.deviceId])
return .success(user)
})
.catchError({ error -> Observable<Result<User>> in
LogService.log(level: .error, action: "postUser", message: "Error posting user", parameters: ["user": user.deviceId, "error": error.localizedDescription])
return Observable.just(.failure(error))
})
}
}
但是,如果我在UserService不需要这个
rxProvider.request(Backend.register(user: user))
...
.subscribe { (event) in
print(event)
}
,我会得到下一个事件。
我曾试着在InfoViewModel的observable上使用debug()
,这里有一个订阅,我从来没有收到任何事件。
添加行号,我认为图像可以更好地显示两个文件。 –
http://meta.stackoverflow.com/questions/285551/why-may-i-not-upload-images-of-code-on-so-when-asking-a-question 我只是想帮助您可以更快地回答您的问题^^ – Keiwan
尽快c/p代码 –