2
我正在尝试给我以下错误的typedQuery: java.lang.IllegalArgumentException:无法为非实体集合创建元素连接!无法为非实体集合创建元素连接
我使用JPA 2.0
我的代码:
@Entity
public class Example {
@ElementCollection(targetClass=ExampleData .class,fetch = FetchType.EAGER)
@MapKeyColumn(name = "locale_key")
@CollectionTable(name = "exampleLocalizedData", joinColumns = @JoinColumn(name = "exampleId"))
private Map<String, IExampleData> exampleLocalizedData;
}
@Embeddable
public class ExampleData {
private String data;
.....
}
我的查询:
String querySentence = "SELECT DISTINCT e FROM Example e WHERE e.exampleLocalizedData[:locale].name LIKE :filter ";
TypedQuery<Example > actualQuery = entityManager.createQuery(querySentence, Example .class);
我的问题是,它是这样做的正确的查询?
问候。
编辑:
最终查询,如果任何想知道:
select DISTINCT e FROM Example e join e.exampleLocalizedData r WHERE index(r) = :locale AND r.name LIKE :filter .
尝试使用明确的'JOIN':'字符串querySentence =“SELECT DISTINCT E从例E JOIN e.exampleLocalizedData场场WHERE [:现场]。名称,如:过滤器“; TypedQuery actualQuery = entityManager.createQuery(querySentence,Example.class);' –
n1ckolas
2013-02-26 13:29:07
给我一个java.lang.UnsupportedOperationException – 2013-02-26 13:44:26
另一个镜头(其他的省略):'FROM示例e JOIN e.exampleLocalizedData [:locale] eld WHERE eld .name LIKE:filter' – n1ckolas 2013-02-26 14:01:59