我必须在表格中显示已打开的作品(1,2,3 ...),其中包括相关任务(1,2,3 ...)的列表,每个连续。任务可能会被打开或关闭。我尝试通过点击类“showhideforwork-x”中的行来找到隐藏/显示特定工作(表格)的关闭任务(行)的方法。在多个元素上显示隐藏多个div
<table class="work-1">
<tr class="showhideforwork-1"><td>Hide closed tasks</td><tr>
<tr><td>Task 1 (opened)</td></tr>
<tr class="showhidework-1"><td>Task 2 (closed)</td></tr>
<tr class="showhidework-1"><td>Task 3 (closed)</td></tr>
<tr><td>Task 4 (opened)</td></tr>
</table>
<table class="work-2">
<tr class="showhideforwork-2"><td>Hide closed tasks</td><tr>
<tr class="showhidework-2"><td>Task 1 (closed)</td></tr>
<tr class="showhidework-2"><td>Task 1 (closed)</td></tr>
<tr><td>Task 3 (opened)</td></tr>
</table>
<table class="work-n">
<tr class="showhideforwork-3"><td>Hide closed tasks</td><tr>
<tr><td>Task 1 (opened)</td></tr>
<tr class="showhidework-n"><td>Task 2 (closed)</td></tr>
<tr class="showhidework-n"><td>Task 3 (closed)</td></tr>
</table>
我想我不使用类的事情应该是这样捉对“showhideforwork-X”元素和隐藏/显示相应的“showhidework-X”行的点击。
它不工作 –
你是对的,而不是隐藏应切换()代替。修复。 – Janar
是的,现在正在正常工作 –