1
我通过下面的代码AngularJS试图建立一个RESTful API接口:为什么我得到“不正确的注射标记!”在这个角度应用程序代码?
'use strict';
(function(angular) {
function ApiAction($resource, ResourceParameters) {
return $resource(ResourceParameters.route,
{ },
{ api_index: {
method: ResourceParameters.method,
isArray: true
}
});
return $resource(ResourceParameters.route,
{ },
{ create: {
method: ResourceParameters.method,
isArray: true
}
}
);
}
function ResourceParameters($scope) {
var factory = {};
factory.method = '';
factory.route = '';
factory.SetMethod = function(method) {
factory.method = method;
}
factory.SetRoute = function(route) {
factory.route = route;
}
return factory;
}
function superheroCtr($scope, ApiAction, ResourceParameters) {
$scope.superheroSubmit = function() {
// ApiAction.create({}, { superhero_name: $scope.superheroName, age: $scope.superheroAge });
angular.forEach($scope.superheroes, function(hero) {
// ApiAction.create({}, { superhero_name: hero.superhero_name, age: hero.age });
});
};
var heroesResources = ResourceParameters($scope).SetRoute('/api/');
var heroes = ApiAction.api_index({}, heroesResources);
$scope.superheroes = [];
heroes.$promise.then(function(data) {
angular.forEach(data, function(item) {
$scope.superheroes.push(item);
});
}, function(data) {
//if error then...
});
$scope.appendSuperheroFields = function() {
var i = $scope.superheroes.length + 1;
$scope.superheroes.push({"id": i, age: "", superhero_name: "" })
}
}
var superheroApp = angular.module('superheroApp', ['ngResource']);
superheroApp.controller('superheroCtr', ['$scope', 'ApiAction', 'ResourceParameters', superheroCtr]);
superheroApp.factory('ResourceParameters', ['$scope', ResourceParameters]);
superheroApp.factory('ApiAction', ['$resource', ResourceParameters, ApiAction]);
})(angular);
然而,当我运行它,我得到以下错误:
错误:[$注射器:itkn ]不正确的注射标记!预期服务名称为字符串,得到函数ResourceParameters($ scope)
这是为什么?
嗯了的
ApiAction
声明,所以如果我这样做,我得到这个:'错误:[$注射器:itkn]不正确的注射标记!预期的服务名称作为字符串,得到的函数ResourceParameters()' – Nona@Nona你是否更改'superheroApp.factory('ResourceParameters',['$ scope',ResourceParameters]);'to'superheroApp.factory('ResourceParameters',[ResourceParameters ]);'&也看看更新的答案 –
谢谢,这修正了那个错误! – Nona