这是我做SQL的第三天,我相信它确实很小。mysqli_fetch_row只适用于第一行
我有这段代码。 $ con是我的SQL连接变量。
for ($i = 0; $i < mysqli_num_rows(mysqli_query($con, "SELECT * FROM offers WHERE active='y'")); $i++)
{
echo '<div class="dottedBox">User: '.mysqli_fetch_row(mysqli_query($con, "SELECT poster FROM offers WHERE active='y'"))[$i]."<br>
Has: ".mysqli_fetch_row(mysqli_query($con, "SELECT haveamt FROM offers WHERE active='y'"))[$i]." ".mysqli_fetch_row(mysqli_query($con, "SELECT have FROM offers WHERE active='y'"))[$i].'<br>
Wants: '.mysqli_fetch_row(mysqli_query($con, "SELECT wantamt FROM offers WHERE active='y'"))[$i].' '.mysqli_fetch_row(mysqli_query($con, "SELECT want FROM offers WHERE active='y'"))[$i].'</div><br>';
}
第一项输出正常。然而,每个后续项目将导致以下错误:
Notice: Undefined offset: 1 in /var/www/civ/index.php on line 6
Notice: Undefined offset: 1 in /var/www/civ/index.php on line 7
Notice: Undefined offset: 1 in /var/www/civ/index.php on line 7
Notice: Undefined offset: 1 in /var/www/civ/index.php on line 8
Notice: Undefined offset: 1 in /var/www/civ/index.php on line 8
运行SELECT * FROM offers;
回报这在MySQL(我使用Debian):
mysql> SELECT * FROM offers;
+----------+-----------+---------+-----------+---------+---------+--------+
| poster | have | haveamt | want | wantamt | offerid | active |
+----------+-----------+---------+-----------+---------+---------+--------+
| minicl55 | gfdsafdsa | 3 | fdsafdsa | 2 | 1 | y |
| minicl55 | jklgdsa | 324 | jfklsdjkl | 4522 | 2 | y |
+----------+-----------+---------+-----------+---------+---------+--------+
我有两个问题:
- 为什么不正确输出
- 我该如何解决这个问题?
您的代码正在重新运行每个for循环中的SQL查询。看来你甚至试图用新的查询单独获取每一列 - 而不是仅仅获取一个数组。 – mario 2014-10-09 23:29:14