2014-10-09 67 views
-2

这是我做SQL的第三天,我相信它确实很小。mysqli_fetch_row只适用于第一行

我有这段代码。 $ con是我的SQL连接变量。

for ($i = 0; $i < mysqli_num_rows(mysqli_query($con, "SELECT * FROM offers WHERE active='y'")); $i++) 
{ 
    echo '<div class="dottedBox">User: '.mysqli_fetch_row(mysqli_query($con, "SELECT poster FROM offers WHERE active='y'"))[$i]."<br> 
    Has: ".mysqli_fetch_row(mysqli_query($con, "SELECT haveamt FROM offers WHERE active='y'"))[$i]." ".mysqli_fetch_row(mysqli_query($con, "SELECT have FROM offers WHERE active='y'"))[$i].'<br> 
    Wants: '.mysqli_fetch_row(mysqli_query($con, "SELECT wantamt FROM offers WHERE active='y'"))[$i].' '.mysqli_fetch_row(mysqli_query($con, "SELECT want FROM offers WHERE active='y'"))[$i].'</div><br>'; 
} 

第一项输出正常。然而,每个后续项目将导致以下错误:

Notice: Undefined offset: 1 in /var/www/civ/index.php on line 6 

Notice: Undefined offset: 1 in /var/www/civ/index.php on line 7 

Notice: Undefined offset: 1 in /var/www/civ/index.php on line 7 

Notice: Undefined offset: 1 in /var/www/civ/index.php on line 8 

Notice: Undefined offset: 1 in /var/www/civ/index.php on line 8 

运行SELECT * FROM offers;回报这在MySQL(我使用Debian):

mysql> SELECT * FROM offers; 
+----------+-----------+---------+-----------+---------+---------+--------+ 
| poster | have  | haveamt | want  | wantamt | offerid | active | 
+----------+-----------+---------+-----------+---------+---------+--------+ 
| minicl55 | gfdsafdsa |  3 | fdsafdsa |  2 |  1 | y  | 
| minicl55 | jklgdsa |  324 | jfklsdjkl | 4522 |  2 | y  | 
+----------+-----------+---------+-----------+---------+---------+--------+ 

我有两个问题:

  • 为什么不正确输出
  • 我该如何解决这个问题?
+0

您的代码正在重新运行每个for循环中的SQL查询。看来你甚至试图用新的查询单独获取每一列 - 而不是仅仅获取一个数组。 – mario 2014-10-09 23:29:14

回答

2

您正在查询循环中每个值的数据库。您只需要查询一次数据库,然后循环显示结果。

$result = mysqli_query($con, "SELECT * FROM offers WHERE active='y'"); 

while ($row = mysqli_fetch_assoc($result)) 
{ 
    echo '<div class="dottedBox">User: '.$row['poster']."<br> 
    Has: ".$row['haveamt']." ".$row['offers'].'<br> 
    Wants: '.$row['wantamt'].' '.$row['offers'].'</div><br>'; 
} 
+0

是的,修复它,谢谢。顺便说一句,你有一个额外的{第三(或第四取决于你如何编写代码)。我无法编辑它,因为它少于7个字符 – Frank 2014-10-09 23:32:38

+0

哎呀,谢谢你的发现。我修好了它。 – slapyo 2014-10-09 23:34:32

相关问题