MySQL表看起来是这样的: 高级PHP上传表单
下面是输出的代码:
<li>
<a class="thumb" href="library/<?php echo $row2['projectname']; ?>/<?php echo $row2['projectrecordnum']; ?>.<?php echo $row2['projectformat']; ?>" title="<?php echo $row2['projectrecordtitle']; ?>">
<img src="library/<?php echo $row2['projectname']; ?>/thumbs/<?php echo $row2['projectrecordnum']; ?>.<?php echo $row2['projectformat']; ?>" alt="<?php echo $row2['projectrecordtitle']; ?>" />
</a>
<div class="caption">
<div class="image-title"><?php echo $row2['projectrecordtitle']; ?></div>
<div class="image-desc"><?php echo $row2['projectrecorddesc']; ?></div>
<div class="download">
<a href="library/<?php echo $row2['projectname']; ?>/<?php echo $row2['projectrecordnum']; ?>.<?php echo $row2['projectformat']; ?>" target="_blank">Download Original</a>
</div>
</div>
</li>
下面是输出的外观:
<li>
<a class="thumb" href="library/ultima/2.jpg" title="Timbo DISPLACED">
<img src="library/ultima/thumbs/2.jpg" alt="Timbo DISPLACED" />
</a>
<div class="caption">
<div class="image-title">Timbo DISPLACED</div>
<div class="image-desc">Made in 3ds Max, background, color and lens flare from Photoshop</div>
<div class="download">
<a href="library/ultima/2.jpg" target="_blank">Download Original</a>
</div>
</div>
</li>
我的问题是,我无法找到一种形式,这将创建一个用户需要的领域,然后将每个文件信息上传并写入一个mysql数据库(请记住文件数量不确定)。
到底是什么你的问题?你的'表格'看起来像什么? – Peon 2012-07-31 14:14:30
目前它只是载有项目名称,项目显示名称,项目格式,项目评论,项目信息 – 2012-07-31 14:26:01
等主要信息所以你想要一个系统,将创建一个未知数量/任意内容的表单字段设置,并处理填充那些谁知道,什么字段到数据库中? – 2012-07-31 14:28:29