Rails关联：在创建操作中保存方法的类型无效

Question

我想通过http和post方法使用rails for server和post数据，然后将数据保存到数据库。为此，我有2个模型和控制器：bolouk和'radif'。 我有关联如下：

models/bolouk.rb：

class Bolouk < ActiveRecord::Base 
    has_many :radifs, :dependent => :destroy 
end 

models/radif.rb：

class Radif < ActiveRecord::Base 
    belongs_to :bolouk 
end 

我可以创建新的bolouk，但是当我想创造新的radif，我送，我需要为所有的方法在数据库中创建新的radif（如bolouk_id和radif参数），并且我在rails服务器和create action中收到了这些数据，但是当我想创建新方法时， 500 Internal Error。

controller/api/v1/radifs_controller.rb：

class Api::V1::RadifsController < Api::V1::BaseController 
    def create 
    @radif = Radif.create(radif_params) 
    if @radif.valid? 
     puts "if" 
     respond_with @radif, :location => api_bolouk_radifs_path 
    else 
     puts "else" 
     respond_with @radif.errors, :location => api_bolouks_radifs_path 
    end 
    end 
    private 
    def radif_params 
    params.require(:radif).permit(:bolouk_id, :describe, :price) 
    end 
end 

我把一些日志中创建行动，我定义控制器检测@radif为invalid，不保存@radif数据库。我把服务器日志如下：

Started POST "/api/bolouks/23/radifs?describe=110&price=128" for 127.0.0.1 at 2014-09-03 16:05:37 +0430 
Processing by Api::V1::RadifsController#create as JSON 
    Parameters: {"bolouk_id"=>"23", "describe"=>"110", "price"=>"128", "radif"=>{"bolouk_id"=>"23"}} 
    User Load (0.0ms) SELECT "users".* FROM "users" WHERE "users"."id" = 7 ORDER BY "users"."id" ASC LIMIT 1 
    (0.0ms) begin transaction 
    (0.0ms) rollback transaction 
else 
Completed 500 Internal Server Error in 27ms (Views: 1.0ms | ActiveRecord: 1.0ms) 

我发送来自angularjs数据，我有下面的代码： newradif.html：

<form ng-submit="saveRadif()" class="form-horizontal" role="form"> 
        <div> 
         <ul> 
          <li ng-repeat="err in errors">{{err}}</li> 
         </ul> 
        </div> 
        <div class="form-group"> 
         <label for="radifdescribe" class="col-sm-2 control-label"><span>Describe:</span></label> 
         <div class="col-sm-4"> 
          <input ng-model='modalRadif.describe' class="form-control" id="radifdescribe" placeholder="describe"> 
         </div> 
        </div> 
        <div class="form-group"> 
         <label for="radifprice" class="col-sm-2 control-label"><span>Price</span></label> 
         <div class="col-sm-4"> 
          <input ng-model="modalRadif.price" class="form-control" id="radifprice" placeholder="price"> 
         </div> 
        </div> 
        <div class="form-group"> 
         <div class="col-sm-offset-2 col-sm-10"> 
          <button type="submit" class="btn btn-success">Create</button> 
         </div> 
        </div> 
       </form> 

和angularjs控制器：

$scope.saveRadif = function(){ 
      Radifs.create($scope.modalRadif, {bolouk_id: $scope.saveBolouk.id}).$promise.then(function(data){ 
       $scope.radifs = Radifs.index({bolouk_id: $scope.saveBolouk.id}); 
    //   $scope.saveRadif = data; 
      }) 
       .catch(function (err) { 
        console.log(err.data); 

       }) 
     } 
app.factory('Radifs', function($resource) { 
    return $resource('/api/bolouks/:bolouk_id/radifs', {bolouk_id: '@bolouk_id'}, { 
     index: { method: 'GET', isArray: true}, 
     create: { method: 'POST' } 
    }); 
}); 

我怎样才能解决这个问题？

Answer 1

在您的模型类中，您已经定义了Bolouk和Radif模型之间的has_many和belongs_to关联。因此，您可以按照以下方式创建属于Bolouk对象的新Radif对象。

def create 
    @bolouk = Bolouk.find(params[:bolouk_id]) 
    @radif = @bolouk.radifs.build(radif_params) 
    if @radif.save 
    respond_with @radif, :location => api_bolouk_radifs_path 
    else 
    respond_with @radif.errors, :location => api_bolouk_radifs_path 
    end  
end