-4
所以我有一个问题,当我添加一个新的节点到列表中时,我的头节点发生了变化。我必须从文件中读取多行。每条线将成为函数f(x)= ...并且节点是函数中的奇异表达式,因此节点1例如可以是25x^2并且节点2可以是15x。所以我的Node类保存系数,所以对于节点1它将是25,并且指数x到达。这是导致我认为的问题的代码段。C++链接列表
Node* n = new Node();
List nodeList;
nodeList.setHead(NULL);
while(not at the end of line)
{
//This while loop just inputs from file, and stores values into Node class.
if(!nodeList.getHead()) //so this is first node being input.
{
//i collect the values for coefficient and exponent here...
n->setCoef(coef);
n->setExp(exp);
nodeList.insertNode(n);
}
else //so this is not the first node in the list.
{
//i collect the values for coefficient and exponent again here...
//After this code below, the head node changes to n's coef and exp.
//I know this is because n is still pointing at the head node
//but I keep getting runtime errors when trying to fix this.
n->setCoef(coef);
n->setExp(exp);
nodeList.insertNode(n);
}
}
这是我的一览:: insertNode(节点* N)类:
void List::insertNode(Node* n){
//if theres no head node, just set it to the n node and continue.
if (!head)
head = n;
else{
Node* ptr = head; //used to traverse through list.
bool likeTerms = false;
while(ptr) //This while loop checks to make sure theres no like terms.
{
if (ptr->getExp() == n->getExp()){
likeTerms = true;
break;
}
ptr = ptr->getNext();
}
//If they aren't like terms, just add the node to the end.
if (!likeTerms){
ptr = head;
while(ptr->getNext() != NULL)
{
ptr = ptr->getNext(); //traverses to the last node in list.
}
ptr->setNext(n); //Adds the new node to the spot after the last node
}
else if (likeTerms == true)//If the x exponents have like terms,
//then just combine them.
ptr->setCoef(ptr->getCoef()+n->getCoef());
}
}
感谢您在改进我的代码方面的帮助。我一定会仔细研究一下。但我发现了这个问题。我的问题措辞不佳,但基本上我只创建了一个节点,并试图将同一节点添加到列表中,但每次都使用不同的值。我用nodeList.insertNode(new Node(coef,exp,NULL))替换了nodeList.insertNode(n);这一行,而不是Node * n。 – CMW
欢迎您。我太关注代码的简化了,只是简单地将代码'Node * n = new Node;'放在while循环中,没有任何解释或评论。因此,我不直接回答你的问题。 – Kai