如何将JSON数组设置为定义类型？

如何设置数组中对象的类型以引用json模式文件的定义部分中的另一个已定义对象？我试过这样做：如何将JSON数组设置为定义类型？

"definitions": { 
    "ObjectA": { 
     "title": "ObjectA", 
     "type": "object", 
     "properties": { 
      "description": { 
       "type": "string" 
      }, 
      "status": { 
       "type": "string" 
      }, 
     }, 
     "required": [ 
      "description", 
      "status" 
     ] 
    }, 
    "ObjectB": { 
     "title": "ObjectB", 
     "type": "object", 
     "properties": { 
      "objectalist": { 
       "type": "array", 
       "items": { 
        "type": { 
         "$ref": "#/definitions/ObjectA" 
        } 
       } 
      } 
     }, 
     "required": [ 
      "objectalist" 
     ] 
    } 
}

和json编辑器似乎认为它很好。这个片段是一个扬鞭API定义的一部分，当我通过代码生成工具来运行它，我得到这个错误：如果我改变对象B到

[main] ERROR io.swagger.codegen.DefaultCodegen - No Type defined for Property null 
Exception in thread "main" java.lang.RuntimeException: Could not process model 'ObjectB'.Please make sure that your schema is correct! 
     at io.swagger.codegen.DefaultGenerator.generate(DefaultGenerator.java:297) 
     at io.swagger.codegen.cmd.Generate.run(Generate.java:223) 
     at io.swagger.codegen.SwaggerCodegen.main(SwaggerCodegen.java:36) 
Caused by: java.lang.NullPointerException 
     at io.swagger.codegen.languages.AbstractJavaCodegen.toModelName(AbstractJavaCodegen.java:400) 
     at io.swagger.codegen.languages.AbstractJavaCodegen.getSwaggerType(AbstractJavaCodegen.java:577) 
     at io.swagger.codegen.DefaultCodegen.getTypeDeclaration(DefaultCodegen.java:1119) 
     at io.swagger.codegen.languages.AbstractJavaCodegen.getTypeDeclaration(AbstractJavaCodegen.java:427) 
     at io.swagger.codegen.languages.AbstractJavaCodegen.toDefaultValue(AbstractJavaCodegen.java:440) 
     at io.swagger.codegen.DefaultCodegen.fromProperty(DefaultCodegen.java:1359) 
     at io.swagger.codegen.DefaultCodegen.addVars(DefaultCodegen.java:2738) 
     at io.swagger.codegen.DefaultCodegen.addVars(DefaultCodegen.java:2709) 
     at io.swagger.codegen.DefaultCodegen.addVars(DefaultCodegen.java:2695) 
     at io.swagger.codegen.DefaultCodegen.fromModel(DefaultCodegen.java:1284) 
     at io.swagger.codegen.languages.AbstractJavaCodegen.fromModel(AbstractJavaCodegen.java:601) 
     at io.swagger.codegen.DefaultGenerator.processModels(DefaultGenerator.java:875) 
     at io.swagger.codegen.DefaultGenerator.generate(DefaultGenerator.java:290) 
     ... 2 more

：

"ObjectB": { 
     "title": "ObjectB", 
     "type": "object", 
     "properties": { 
      "objectalist": { 
       "type": "array", 
       "items": { 
        "type": "string" 
       } 
      } 
     }, 
     "required": [ 
      "objectalist" 
     ] 
    }

的代码生成作品。有没有办法将数组中的对象类型设置为定义的类型？

来源

2016-09-28 sdoca

在另一篇文章中找到了关于定义自定义JSON类型的答案。答案是删除封闭的"type":。所以，看起来像这样：

"ObjectB": { 
     "title": "ObjectB", 
     "type": "object", 
     "properties": { 
      "objectalist": { 
       "type": "array", 
       "items": { 
        "$ref": "#/definitions/ObjectA" 
       } 
      } 
     }, 
     "required": [ 
      "objectalist" 
     ] 
    }

来源

2016-09-28 21:38:10 sdoca

如何将JSON数组设置为定义类型？

回答

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