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我一直在玩AchartEngine一两天了。我修改了TrignometricFunctionsChart以显示各种可能的图形。现在我想让用户输入函数并绘制该函数的图形。为此,我需要一个EditText和一个Button里面的图表。我试着读Android: I am using AChartEngine library for graphs, but not able to integrate achartengine's graph view with android xml?却无法完成任务。我尝试编辑XYChartBuilder(唯一包含在XML文件中的图表),但无法将TrignometricFunctionsChart插入它。Achartengine:以XML显示视图
我不知道如何迁移这个代码片段:
public Intent execute(Context context) {
String[] titles = new String[] { "sin", "cos" };
List<double[]> x = new ArrayList<double[]>();
List<double[]> values = new ArrayList<double[]>();
int step = 4;
int count = 360/step + 1;
x.add(new double[count]);
x.add(new double[count]);
double[] sinValues = new double[count];
double[] cosValues = new double[count];
values.add(sinValues);
values.add(cosValues);
for (int i = 0; i < count; i++) {
int angle = i * step;
x.get(0)[i] = angle;
x.get(1)[i] = angle;
double rAngle = angle/57.295779513082;
sinValues[i] = rAngle;
cosValues[i] = 0.25*rAngle;
}
int [] colors = new int[] { Color.BLUE, Color.CYAN };
PointStyle[] styles = new PointStyle[] { PointStyle.POINT, PointStyle.POINT };
XYMultipleSeriesRenderer renderer = buildRenderer(colors, styles);
setChartSettings(renderer, "Trigonometric functions", "X (in degrees)", "Y", 0, 360, -1, 1,
Color.GRAY, Color.LTGRAY);
renderer.setXLabels(20);
renderer.setYLabels(10);
return ChartFactory.getLineChartIntent(context, buildDataset(titles, x, values), renderer);
}
我尝试了很多我的朋友。正如我所提到的,我甚至修改了代码来显示复杂函数的图形。我唯一无法理解的是如何将上面的代码插入到XYChartBuilder中。 – 2012-08-03 13:38:00